\(\left|x+\dfrac{1}{5}\right|-4=\dfrac{2}{3}\)
\(\Rightarrow\left|x+\dfrac{1}{5}\right|=\dfrac{2}{3}+4\)
\(\Rightarrow\left|x+\dfrac{1}{5}\right|=\dfrac{2}{3}+\dfrac{12}{3}\)
\(\Rightarrow\left|x+\dfrac{1}{5}\right|=\dfrac{14}{3}\)
\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{14}{3}\\x+\dfrac{1}{5}=-\dfrac{14}{3}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{67}{15}\\x=-\dfrac{73}{15}\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=\dfrac{67}{15}\\x=-\dfrac{73}{15}\end{matrix}\right.\)