Question

(x-2)²⁰¹²+/y²-9/²⁰¹⁴=0
/ / là trị tuyệt đối nhé
làm gấp hộ mik dễ hiểu ngắn gọn thôi nhé

Answer 1

Ta có :

\(\left\{{}\begin{matrix}\left(x-2\right)^{2012}\ge0\\\left|y^2-9\right|^{2014}\ge0\end{matrix}\right.\)

Lại có : \(\left(x-2\right)^{2012}+\left|y^2-9\right|^{2014}=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}\left(x-2\right)^{2012}=0\\\left|y^2-9\right|^{2014}=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x-2=0\\y^2-9=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=2\\y^2=9\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=2\\\left[{}\begin{matrix}y=3\\y=-3\end{matrix}\right.\end{matrix}\right.\)

Vậy ..

Answer 2

Vì (x-2)²⁰¹² ≥ 0

/y² -9/²⁰¹⁴ ≥ 0

=> (x-2)²⁰¹² + /y² -9/²⁰¹⁴ = 0

=> (x-2)²⁰¹² = 0

/y² -9/²⁰¹² = 0

=> x-2 = 0

y² -9 = 0

=> x = 2

y² = 9

=> x=2

y = 3 hoặc -3

Vậy x=2

y = 3 hoặc -3

Answer 3

\(\Rightarrow\left[{}\begin{matrix}x-2=0\\y^2-9=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\y=\pm3\end{matrix}\right.\)