\(\dfrac{2x+y}{x-y}=\dfrac{1}{2}\) (ĐKXĐ: \(x\ne y;y\ne0\))
\(\Leftrightarrow4x+2y=x-y\)
\(\Leftrightarrow4x-x=-y-2y\)
\(\Leftrightarrow3x=-3y\)
\(\Leftrightarrow\dfrac{x}{y}=-\dfrac{3}{3}=-1\) hay \(P=-1\)
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