Question

Tính

\(sin^4.x=\left(sin^2x\right)^2\)

a) A= \(\left(cos.x+sin.x\right)^2+\left(sin.x-cos.x\right)^2\)

b) B= \(sin^4.x-cos^4.x-2sin^2.x+1\)

c) C= \(2cos^4.x-sin^4.x+sin^2.x.cos^2.x+3sin^2.x\)

d) D= \(\left(cot.x+tan.x\right)^2-\left(cot.x-tan.x\right)^2\)

e) E= \(\sqrt{1+cos.x}.\sqrt{1-cosx}\)

f) F= \(sin.x\sqrt{1+tan^2x}\)

g) G= \(sin\left(180-x\right).cot\left(180-x\right)\)

h) H= \(cot.x\left(\frac{1+sin^2.x}{cos.x}-cos.x\right)\)

Answer 1

Chẹp ko hỉu đề boài :)