tính x, y, z biết
a) \(\dfrac{x}{2}=\dfrac{y}{3},\dfrac{y}{5}=\dfrac{z}{7}\), x + y + z = 92
b) 2x = 3y = 5z, x + y - z = 95
c) \(\dfrac{x}{y+x+1}=\dfrac{y}{x+z+1}=\dfrac{z}{x+y-2}=x+y+z\)
\(\dfrac{x}{y+z+1}\)=\(\dfrac{y}{x+z+1}\)=\(\dfrac{z}{x+y-2}\)=x+y+z giúp mik vs
a) \(\dfrac{x}{10}=\dfrac{y}{15}=\dfrac{z}{-21}\\ \) và x+y+z =92
b) \(\dfrac{x}{5}=\dfrac{y}{1}=\dfrac{z}{-2}\) và x+y-2z =160
c) 4x=3y=3z và x+y+z=1975
tim x,y,z biết
\(\dfrac{y+a+9}{x}=\dfrac{x+z+2}{y}=\dfrac{x+z-3}{z}=\dfrac{1}{x+y+z}\)
bài tìm x,y,z biết :a)\(\dfrac{x}{5}=\dfrac{y}{6};\dfrac{y}{8}=\dfrac{z}{7}\)và x+y-z=69
b)\(\dfrac{x}{3}=\dfrac{y}{4};\dfrac{y}{3}=\dfrac{z}{5}\)và 2x-3y+z=6
c)\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{z}{6}\)và x+y=14
d)\(\dfrac{2}{3x}=\dfrac{1}{2y}=\dfrac{2}{z}\)và 3x+2y+z=1
tìm x,y,z biết
\(\dfrac{x}{x+y+1}=\dfrac{y}{x+z+1}=\dfrac{z}{x+y-2}=x+y+z\)
cho x,y,z khác 0 thỏa mãn: \(\dfrac{x}{1}=\dfrac{y}{2}=\dfrac{z}{3}\). CMR: ( x+y+z ). \(\left(\dfrac{1}{x}+\dfrac{4}{y}+\dfrac{9}{z}\right)\)
\(\dfrac{y+z+1}{x}\)=\(\dfrac{z+x+2}{y}\)=\(\dfrac{x+y-3}{z}\)=\(\dfrac{1}{x+y+z}\)
Tìm số nguyên x,y,z thỏa mãn điều kiện sau : \(\dfrac{x}{y}+\dfrac{y}{z}+\dfrac{z}{x}=\dfrac{y}{x}+\dfrac{z}{y}+\dfrac{x}{z}=x+y+z=3\)
