\(\left(x-\frac{2}{3}\right)^2=\frac{49}{4}\)
\(\Rightarrow\left(x-\frac{2}{3}\right)^2=\left(\pm\frac{7}{2}\right)^2\)
\(\Rightarrow x-\frac{2}{3}=\pm\frac{7}{2}.\)
\(\Rightarrow\left[{}\begin{matrix}x-\frac{2}{3}=\frac{7}{2}\\x-\frac{2}{3}=-\frac{7}{2}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{7}{2}+\frac{2}{3}\\x=\left(-\frac{7}{2}\right)+\frac{2}{3}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{25}{6}\\x=-\frac{17}{6}\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{25}{6};-\frac{17}{6}\right\}.\)
Chúc bạn học tốt!
(x-2/3)^2=(7/2)^2
=>x-2/3=7/2
=>x=7/2+2/3
=>x=25/6
Nhớ tích cho mk nha
\(\left(x-\frac{2}{3}\right)^2=\frac{49}{4}\)
\(\left(x-\frac{2}{3}\right)^2=\left(\frac{7}{2}^2\right)\)
\(x-\frac{2}{3}=\frac{7}{2}\)
\(x=\frac{7}{2}+\frac{2}{3}\)
\(x=\frac{25}{6}\)