\(\dfrac{2^{2x-3}}{4^{10}}=8^3.16^5\)
=> \(2^{2x-3}:4^{10}=8^3.16^5\)
=> \(2^{2x-3}.\left(2^2\right)^{10}=\left(2^3\right)^3.\left(2^4\right)^5\)
=> \(2^{2x-3}:2^{20}=2^9.2^{20}\)
=> \(2^{2x-3}:2^{20}\) = 229
=> \(2^{2x-3-20}=2^{29}\)
\(\Leftrightarrow\) \(2x-3-20=29\)
=> \(2x-3=29+20\)=49
=> \(2x=49+3\) = 52
=> \(x=52:2\) => x=26
a) \(\dfrac{5^5}{5^x}=5^{18}\)
b) \(\dfrac{2^{4-x}}{16^5}=32^6\)
c) \(\dfrac{2^{2x-3}}{4^{10}}=8^3.16^5\)
d) \(\dfrac{2^3}{2^x}=4^5\)
e) \(9.5^x=6.5^6+3.5^6\)
f) \(7.2^x=2^9+5.2^8\)
Tìm x, y, z biết:
\(2x+3y+4z=10\\ \dfrac{x}{3}=\dfrac{y}{4}=\dfrac{z}{5}\)
Tìm x,biết: a)x : \((\dfrac{3}{4})^{3} = (\dfrac{3}{4})^{2} \) b) \(\dfrac{2}{5}^{5} . x = \dfrac{2}{5}^{8}\)
Trong vở bài tập của bạn Dũng có bài làm sau :
a) \(\left(-5\right)^2.\left(-5\right)^3=\left(-5\right)^6\)
b) \(\left(0,75\right)^3:0,75=\left(0,75\right)^2\)
c) \(\left(0,2\right)^{10}:\left(0,2\right)^5=\left(0,2\right)^2\)
d) \(\left[\left(-\dfrac{1}{7}\right)^2\right]^4=\left(-\dfrac{1}{7}\right)^6\)
e) \(\dfrac{50^3}{125}=\dfrac{50^3}{5^3}=\left(\dfrac{50}{5}\right)^3=10^3=1000\)
Hãy kiểm tra lại các đáp số và sửa lại chỗ sai (nếu có)
f) \(\dfrac{8^{10}}{4^8}=\left(\dfrac{8}{4}\right)^{10-8}=2^2\)
tìm x biết: x:\((\dfrac{3}{4})^3=(\dfrac{3}{4})^2\)
b) \((\dfrac{2}{5})^5.x=(\dfrac{2}{5})^8\)
a. \(\dfrac{81}{3^{2x+1}}=3\)
b.\(2^x+2^{x+2}=80\)
c.\(\dfrac{16^{x+2}}{8^x}=4^5\)
d. \(2^x+2^{x+1}+2^{x+2}=112\)
x:[ \(\dfrac{8}{5}\) . (\(\dfrac{2}{3}\))\(^2\) - \(\dfrac{2}{5}\) ] = \(\dfrac{15}{7}+\dfrac{6}{5}\) [(2\(\dfrac{1}{7}\))\(^2\) - \(\dfrac{50}{49}\) ]
tìm x
giúp mk nhó
tìm x biết
a) \(\dfrac{2}{5}-\left(\dfrac{1}{10}-x\right)=\left(\dfrac{-2}{5}-\dfrac{1}{2}\right)^2\)
b) \(\dfrac{2}{5}-\dfrac{3}{5}\left(x-2\right)=\left(\dfrac{-1}{2}\right)^3-\left(\dfrac{3}{4}\right)^3.\left(-2\right)^2\)
BT4:Tìm x, biết:
a) \(x\div\left(\dfrac{3}{4}\right)^3=\left(\dfrac{3}{4}\right)^2\)
b) \(\left(\dfrac{2}{5}\right)^5\div x=\left(\dfrac{2}{5}\right)^8\)
