Question

Tìm x, biết:

\(^{x^2-12=0}\)

Answer 1

\(x^2-12=0\)

\(x^2=0+12\)

\(x^2=12\)

\(x=\sqrt{12}\) hoặc \(x=-\sqrt{12}\)

Answer 2

\(x^2-12=0\)

\(\Leftrightarrow x^2=12\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\sqrt{12}\\x=-\sqrt{12}\end{matrix}\right.\)

Vậy...