\(\left(\dfrac{4}{9}\right)^{x+1}=\left(\dfrac{8}{27}\right)^6\)
\(\Leftrightarrow\left(\dfrac{2}{3}\right)^{2x+2}=\left(\dfrac{2}{3}\right)^{18}\)
\(\Leftrightarrow2x+2=18\Leftrightarrow2x=16\Leftrightarrow x=8\)
\(\left(\dfrac{4}{9}\right)^{x+1}=\left(\dfrac{8}{27}\right)^6\)
\(\Leftrightarrow\left(\dfrac{2}{3}\right)^{2x+2}=\left(\dfrac{2}{3}\right)^{18}\)
\(\Leftrightarrow2x+2=18\Leftrightarrow2x=16\Leftrightarrow x=8\)
tìm x biết (4/9)x+1=(8/27)^6
Tính:
( -x )\(^8\) : x\(^2\) ( x \(\ne\) 0)
27\(^8\) : 9\(^4\)
tìm x biết (-2/3)^x=-8/27
\(\left(\dfrac{1}{8}\right)^{x^{ }}.27^{2x}=\left(-9\right)^4\)
Tìm x, biết:
1/\(\dfrac{3^{x+5}}{9^3}=27^4\)
Tìm \(x\), biết :
a) \(\left(2x+3\right)^2=\dfrac{9}{121}\)
b) \(\left(3x-1\right)^3=-\dfrac{8}{27}\)
1) Chứng minh rằng :
a) 817-279+329\(⋮\)33
b) 109+108+107\(⋮\)55
c)\(\dfrac{9^{11}-9^{10}-9^9}{639}\in N\)
d)817-279-913\(⋮\)45
2) Tìm x \(\in\) N*
a)27<3x<3.81
b)415.915<2x.3x<1816.216
c)(2x-1)6=(2x-1)8
Các bạn giúp mình nha
Tìm x,y biết :
1) 5x+5x+2=650
2) xy=x4
3) ( x-11+y )2 + ( x-4-y ) 2 = 0
4) ( 3x-5 ) + ( 2y+1 ) 200 < 0
5) 2x=4y-1 và 27y=3x+8
6) 10x:5y=20y
7) 2x+1.3y=22x.3x
Tìm số nguyên x, nếu biết:
a.32x+2=910
b.33x-=2713
c.2x=46.163
d.2x=325.646