\(\dfrac{3}{5x}+\dfrac{1}{5}=\dfrac{-3}{5}\)
\(\dfrac{3}{5x}=\dfrac{-3}{5}-\dfrac{1}{5}\)
\(\dfrac{3}{5x}=\dfrac{-4}{5}\)
\(5x=\dfrac{3.5}{-4}\)
\(5x=\dfrac{-15}{4}\)
\(x=\dfrac{-15}{4}:5\)
\(x=\dfrac{-15}{4}.\dfrac{1}{5}\)
\(x=\dfrac{-3}{4}\)
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Ta có: \(\dfrac{3}{5x}+\dfrac{1}{5}=\dfrac{-3}{5}\)
=> \(\dfrac{3}{5x}=\dfrac{-3}{5}-\dfrac{1}{5}\)
=> \(\dfrac{3}{5x}=\dfrac{-4}{5}\)
=> \(3.5=-4.5x\)
=> \(15=-20x\)
=> \(x=\dfrac{15}{-20}\)
=> \(x=\dfrac{-3}{4}\)
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