\(x:y:z=3:5:\left(-2\right)\)
\(\Rightarrow\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{-2}\)
Áp dụng t/c dtsbn:
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{-2}=\dfrac{5x}{15}=\dfrac{3z}{-6}=\dfrac{5x-y+3z}{15-5-6}=-\dfrac{16}{4}=-4\)
\(\Rightarrow\left\{{}\begin{matrix}x=\left(-4\right).3=-12\\y=\left(-4\right).5=-20\\z=\left(-4\right).\left(-2\right)=8\end{matrix}\right.\)