Ta có:
\(2a=3b=5c\Leftrightarrow\dfrac{30a}{15}=\dfrac{30b}{10}=\dfrac{30c}{6}\\ \Rightarrow\dfrac{a}{15}=\dfrac{b}{10}=\dfrac{c}{6}va`a-b+c=11\)
AD t/c DTS = nhau ta có:
\(\dfrac{a}{15}=\dfrac{b}{10}=\dfrac{c}{6}=\dfrac{a-b+c}{15-10+6}=\dfrac{11}{11}=1\)
+) \(\dfrac{a}{15}=1\Rightarrow a=15\)
+) \(\dfrac{b}{10}=1\Rightarrow b=10\)
+) \(\dfrac{c}{6}=1\Rightarrow c=6\)
Vậy \(a=15;b=10;c=6\)