Question

giải phương trình

6x^2 + x=0

Answer 1

`6x^2+x=0`

`<=>x(6x+1)=0`

`<=>` \(\left[ \begin{array}{l}x=0\\6x=-1\end{array} \right.\) 

`<=>` \(\left[ \begin{array}{l}x=0\\x=-\dfrac16\end{array} \right.\) 

Vậy `S={0;-1/6}`

Answer 2

Ta có: \(6x^2+x=0\)

\(\Leftrightarrow x\left(6x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{1}{6}\end{matrix}\right.\)