Question

\(\frac{x+4}{x+3}+\frac{12x+7}{\left(x+3\right)\left(x+4\right)}=\frac{1-2x}{4-x}\)

Help!!!

Answer 1

\(\frac{x+4}{x+3}+\frac{12x+7}{\left(x+3\right)\left(x+4\right)}=\frac{1-2x}{4-x}\)\(\left(x\ne3,x\ne\pm4\right)\)

\(\frac{x+4}{x+3}+\frac{12x+7}{\left(x+3\right)\left(x+4\right)}+\frac{1-2x}{x-4}=0\)

\(\Leftrightarrow\left(x+4\right)^2\left(x-4\right)+\left(12x+7\right)\left(x-4\right)+\left(1-2x\right)\left(x+4\right)\left(x+3\right)=0\)

\(\Leftrightarrow-x^3+3x^2-74x-80=0\)

Pt nghiệm vô tỉ

(P/s: Làm hơi tắt mà số to không bt đúng không nữa>>>)