Question

\(\dfrac{x}{y}=\dfrac{17}{3}vàx+y=-60\)

Answer 1

Lời giải:

\(\frac{x}{y}=\frac{17}{3}\Rightarrow \frac{x}{y}+1=\frac{17}{3}+1\)

\(\Rightarrow \frac{x+y}{y}=\frac{20}{3}\)

Thay \(x+y=-60\) ta có: \(\frac{-60}{y}=\frac{20}{3}\Rightarrow y=\frac{-60.3}{20}=-9\)

\(\Rightarrow x=-60-y=-60-(-9)=-51\)

Vậy \((x,y)=(-51, -9)\)

Answer 2

Ta có :

\(\dfrac{x}{y}=\dfrac{17}{3}\Rightarrow\dfrac{x}{17}=\dfrac{y}{3}\)

Áp dụng tính chất dãy tỉ số bằng nhau , ta có :

\(\dfrac{x}{17}=\dfrac{y}{3}=\dfrac{x+y}{17+3}=\dfrac{-60}{20}=-30\) ( Do x + y = -60 )

+) \(\dfrac{x}{17}=-30\Rightarrow x=-30.17=-510\)

+) \(\dfrac{y}{3}=-30\Rightarrow y=-30.3=-90\)

Vậy x = -510 , y = -90