HCl + NaOH → NaCl + H2O (1)
\(m_{HCl}=550\times3,65\%=20,075\left(g\right)\)
\(\Rightarrow n_{HCl}=\frac{20,075}{36,5}=0,55\left(mol\right)\)
a) Theo pT1: \(n_{NaOH}=n_{HCl}=0,55\left(mol\right)\)
\(\Rightarrow m_{NaOH}=0,55\times40=22\left(g\right)\)
\(\Rightarrow m_{ddNaOH}=\frac{22}{4\%}=550\left(g\right)\)
b) HCl + AgNO3 → AgCl↓ + HNO3 (2)
Theo PT2: \(n_{AgNO_3}=n_{HCl}=0,55\left(mol\right)\)
\(\Rightarrow m_{AgNO_3}=0,55\times170=93,5\left(g\right)\)
\(\Rightarrow m_{ddAgNO_3}=\frac{93,5}{17\%}=550\left(g\right)\)
Theo PT2: \(n_{AgCl}=n_{HCl}=0,55\left(mol\right)\)
\(\Rightarrow m_{AgCl}=0,55\times143,5=78,925\left(g\right)\)
mHCl = 550*3.65/100=20.075g
nHCl = 0.55 mol
NaOH + HCl --> NaCl + H2O
0.55____0.55
mNaOH = 0.55*40 = 22g
mddNaOH =m = 22*100/4 = 550g
AgNO3 + HCl --> AgCl + HNO3
0.55_____0.55____0.55
mAgCl = 0.55*143.5=78.925g
mAgNO3 = 0.55*170=93.5g
mdd AgNO3 = 93.5*100/17=550g