AC=căn 10^2-6^2=8cm
AH=6*8/10=4,8cm
\(AD=\dfrac{2\cdot6\cdot8}{6+8}\cdot cos45=\dfrac{24}{7}\sqrt{2}\left(cm\right)\)
\(HD=\sqrt{AD^2-AH^2}=\dfrac{24}{35}\left(cm\right)\)
AD là phân giác
=>DB/AB=DC/AC
=>DB/3=DC/4=(DB+DC)/(3+4)=10/7
=>DB=30/7cm; DC=40/7cm