\(P=\dfrac{4\sqrt{x}}{4\left(\sqrt{x}+2\right)}=\dfrac{\sqrt{x}}{\sqrt{x}+2}>=0\)
=>P=|P|
Ta có : \(P=\dfrac{4\sqrt{x}}{4\sqrt{x}+8}\left(x\ge0\right)\)
\(P=\dfrac{4\sqrt{x}}{4.(\sqrt{x}+2)}\)
\(\Rightarrow P=\dfrac{\sqrt{x}}{\sqrt{x}+2}\)
Vì : \(\sqrt{x}\ge0;\sqrt{x}+2\ge2\)
\(\Rightarrow P\ge0\)
Do đó : \(P=\left|P\right|\) ( vì cả hai đều dương )