Question

(5x-1)(2x-\(\dfrac{1}{3}\))=0

Answer 1

\(\left(5x-1\right).\left(2x-\dfrac{1}{3}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}5x-1=0\\2x-\dfrac{1}{3}=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}5x=1\\2x=\dfrac{1}{3}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=\dfrac{1}{6}\end{matrix}\right.\)

Answer 2

(5x-1)(2x-1/3)=0

TH1: 5x-1=0

=>5x=1

=>x=1/5

TH2: 2x-1/3=0

=>2x=1/3

=>x=1/6

Vậy xE{1/5;1/6}