Question

(3x-1)x(2x-3)x(2x-3)x(x+5)

Answer 1

mình viết hơi thiếu:

(3x-1)x(2x-3)x(2x-3)x(x+5)=0

bây giờ mới đúng câu hỏi nhé

 

 

Answer 2

Ta có: \(\left(3x-1\right)\left(2x-3\right)\left(2x-3\right)\left(x+5\right)=0\)

\(\Leftrightarrow\left(3x-1\right)\left(2x-3\right)^2\cdot\left(x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-1=0\\2x-3=0\\x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=1\\2x=3\\x=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=\dfrac{3}{2}\\x=-5\end{matrix}\right.\)

Vậy: \(S=\left\{\dfrac{1}{3};\dfrac{3}{2};-5\right\}\)