Ta có : \(3^{34}=\left(3^{17}\right)^2=129140163^2\) \(5^{20}=\left(5^{10}\right)^2=9765625^2\) Vì 129140163>9765625 nên \(129140163^2>9765625^2\) Vậy \(3^{34}>5^{20}\)Câu trả lời: Ta có : \(3^{34}=\left(3^{17}\right)^2=129140163^2\) \(5^{20}=\left(5^{10}\right)^2=9765625^2\) Vì 129140163>9765625 nên \(129140163^2>9765625^2\) Vậy \(3^{34}>5^{20}\)