\(2x+\dfrac{1}{5}\left(x-5\right)=\dfrac{17}{5}\)
<=> 2x + \(\dfrac{1}{5}x-1=\dfrac{17}{5}\)
<=> \(2x+\dfrac{1}{5}x=\dfrac{22}{5}\)
<=> \(\dfrac{11}{5}x=\dfrac{22}{5}\)
<=> 11x = 22
<=> x =2
\(2x+\dfrac{1}{5}\left(x-5\right)=\dfrac{17}{5}\)
\(2x+\dfrac{1}{5}x-1=\dfrac{17}{5}\)
\(\left(2+\dfrac{1}{5}\right)x=\dfrac{17}{5}+1\)
\(\dfrac{11}{5}x=\dfrac{22}{5}\)
\(x=2\)