Question

2^x-1+5*2^x-2=7/32

Answer 1

\(2^{x+1}+5.2^{x-2}=\dfrac{7}{32}\) ( đề sai )

Ta có:\(2^{x+1}+5.2^{x-1}=\dfrac{7}{32}\)

\(2^{x+1}.\left(1+5\right)=\dfrac{7}{32}\)

\(2^{x-1}=\dfrac{7}{32}:6\)

\(2^{x-1}=\dfrac{7}{192}\)

mà \(2^{x-1}\ne\dfrac{7}{192}\)

\(\Rightarrow x\in\varnothing\)