Question

1,2x :\(\dfrac{5}{7}\)=\(\dfrac{14}{15}\) : \(\dfrac{3}{2}\)

2,\(\dfrac{9}{10}\) :(3x) = \(\dfrac{5}{3}:\dfrac{20}{27}\)

3,\(\dfrac{x-2}{27}=\dfrac{3}{x-2}\)

4,\(\dfrac{2x+5}{9-2x}=\dfrac{2}{5}\)

5,\(\dfrac{x-7}{x+8}=\dfrac{x-8}{x+9}\)

Answer 1

3. Từ \(\dfrac{x-2}{27}=\dfrac{3}{x-2}\Rightarrow\left(x-2\right)^2=81\)

\(\Rightarrow\left(x-2\right)^2=\left(\pm9\right)^2\\ \Rightarrow\left[{}\begin{matrix}x-2=-9\\x-2=9\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-7\\x=11\end{matrix}\right.\)

Vậy x = -7 hoặc x = 11

4. Từ \(\dfrac{2x+5}{9-2x}=\dfrac{2}{5}\)

\(\Rightarrow5\left(2x+5\right)=2\left(9-2x\right)\\ \Leftrightarrow10x+25=18-4x\\ \Leftrightarrow14x=-7\\ \Rightarrow x=-\dfrac{1}{2}\)

5. Từ \(\dfrac{x-7}{x+8}=\dfrac{x-8}{x+9}\)

\(\Rightarrow\left(x-7\right)\left(x+9\right)=\left(x-8\right)\left(x+8\right)\\ \Leftrightarrow x^2+2x-63=x^2-64\\ \Leftrightarrow2x=-1\\ \Rightarrow x=-\dfrac{1}{2}\)