Question

1. Tìm x

\(2\dfrac{1}{2}-x+\dfrac{4}{5}=\dfrac{2}{3}-\left(-\dfrac{4}{7}\right)\)

Answer 1

Giúp mình với 

Answer 2

\(\Leftrightarrow\dfrac{5}{2}-x+\dfrac{4}{5}=\dfrac{26}{21}\\ \Leftrightarrow\dfrac{33}{10}-x=\dfrac{26}{21}\\ \Leftrightarrow x=\dfrac{33}{10}-\dfrac{26}{21}=\dfrac{433}{210}\)

Answer 3

Ta có: \(\dfrac{3}{2}-x+\dfrac{4}{5}=\dfrac{2}{3}-\left(-\dfrac{4}{7}\right)\)

\(\Leftrightarrow\dfrac{23}{10}-x=\dfrac{2}{3}+\dfrac{4}{7}=\dfrac{26}{21}\)

hay \(x=\dfrac{223}{210}\)

Answer 4

\(2\dfrac{1}{2}-x+\dfrac{4}{5}=\dfrac{2}{3}-\dfrac{-4}{7}\)

<=> \(2-x+\dfrac{4}{5}=\dfrac{2}{3}+\dfrac{4}{7}\)

<=> \(2+\dfrac{4}{5}-\dfrac{2}{3}-\dfrac{4}{7}=x\)

<=> x = \(\dfrac{164}{105}\)

Answer 5

Ai đúng vậy nhỉ