Question

Answer 1

2x+x+70+80=360

=>3x=210

=>x=70

=>góc Q=140 độ, góc P=70 độ

Answer 2

Ta có :

\(\widehat{M}+\widehat{Q}+\widehat{N}+\widehat{P}=360^0\) ( tổng các góc trong tứ giác )

\(\Rightarrow\) \(70^0+2x+80^0+x=360^0\)

\(\Rightarrow\)\(70^0+3x+80^0=360^0\)

\(\Rightarrow\)\(3x=210^0\)

\(\Rightarrow\)\(x=70^0\)

\(\Rightarrow\)\(\widehat{P}=70^0\) và \(\widehat{Q}=2x=2.70^0=140^0\)

Vậy \(\widehat{P}=70^0\) ; \(\widehat{Q}=140^0\)