Question

Answer 1

Xét tứ giác ABCD có góc A+góc B+góc C+góc D=360 độ

mà góc C=góc D

nên \(\widehat{C}=\widehat{D}=\dfrac{360^0-95^0-65^0}{2}=100^0\)

Answer 2

Ta có: \(\widehat{A}+\widehat{B}+\widehat{C}+\widehat{D}=360^0\)(tổng 4 góc tứ giác)

\(\Rightarrow95^0+65^0+2\widehat{C}=360^0\)

\(\Rightarrow160^0+2\widehat{C}=360^0\)

\(\Rightarrow2\widehat{C}=200^0\Rightarrow\widehat{C}=100^0=\widehat{D}\)