\(a,2^{33}=8^{11}< 9^{11}=3^{22}\\ b,5^{30}=125^{10}< 243^{10}=3^{50}\\ \Rightarrow\left(-5\right)^{30}< \left(-3\right)^{50}\\ c,\left(\dfrac{1}{27}\right)^{10}=\left(\dfrac{1}{3}\right)^{30}>\left(\dfrac{1}{3}\right)^{28}=\left(\dfrac{1}{81}\right)^7\\ d,80^5< 625^5=\left(5^4\right)^5=5^{20}\)
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