Giá trị của \(x\) thỏa mãn \(-x+\dfrac{1}{7}=3-1\dfrac{1}{2}\) là
\(x=-\dfrac{19}{14}.\)\(x=\dfrac{19}{14}.\)\(x=\dfrac{33}{14}.\)\(x=-\dfrac{33}{14}.\)Hướng dẫn giải:\(-x+\dfrac{1}{7}=3-1\dfrac{1}{2}\)
\(-x+\dfrac{1}{7}=3-\dfrac{3}{2}\)
\(-x+\dfrac{1}{7}=\dfrac{3}{2}\)
\(x=\dfrac{1}{7}-\dfrac{3}{2}\)
\(x=-\dfrac{19}{14}.\)
