Tính:

a) \(-3\frac{3}{4}+\left(-\frac{10}{25}\right)+\left(-\frac{6}{12}\right)\)

\(=\left(-\frac{15}{4}\right)+\left(-\frac{10}{25}\right)+\left(-\frac{6}{12}\right)\)

\(=\left(-\frac{83}{20}\right)+\left(-\frac{6}{12}\right)\)

\(=-\frac{93}{20}.\)

b) \(-0,6-\left(-\frac{4}{9}\right)-\frac{16}{15}\)

\(=\left(-\frac{3}{5}\right)-\left(-\frac{4}{9}\right)-\frac{16}{15}\)

\(=\left(-\frac{7}{45}\right)-\frac{16}{15}\)

\(=-\frac{11}{9}.\)

Chúc bạn học tốt!

\(2\frac{2}{3}:\left\{\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}+2,8\right\}-\frac{7}{15}=0,2\)

\(2\frac{2}{3}:\left\{\left[\left(3,75-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}+2,8\right\}=\frac{2}{3}\)

\(\left\{\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}+2,8\right\}=4\)

\(\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}=\frac{6}{5}\)

\(\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]=1\)

\(\left(3,72-0,02.x\right)=\frac{37}{10}\)

\(0,02.x=0,02\)

\(x=1\)

\(2\frac{2}{3}:\left\{\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}+2,8\right\}-\frac{7}{15}=0,2\)

\(\Rightarrow\frac{8}{3}:\left\{\left[\left(\frac{93}{25}-\frac{1}{50}.x\right)\frac{10}{37}\right]:\frac{5}{6}+\frac{14}{5}\right\}-\frac{7}{15}=\frac{1}{5}\)

\(\Rightarrow\left\{\left[\frac{93}{25}-\frac{1}{50}.x\right]:\frac{5}{6}+\frac{14}{5}\right\}-\frac{7}{15}=\frac{8}{3}:\frac{1}{5}=\frac{40}{3}\)

\(\Rightarrow\left[\frac{93}{25}-\frac{1}{50}.x\right]:\frac{5}{6}+\frac{14}{5}=\frac{40}{3}+\frac{7}{15}=\frac{69}{5}\)

\(\Rightarrow\left[\frac{93}{25}-\frac{1}{50}.x\right]:\frac{5}{6}=\frac{69}{5}-\frac{14}{5}=11\)

\(\Rightarrow\frac{93}{25}-\frac{1}{50}.x=11.\frac{5}{6}=\frac{55}{6}\)

\(\Rightarrow\frac{1}{50}.x=\frac{93}{25}-\frac{55}{6}=\frac{-817}{150}\)

\(\Rightarrow x=\frac{-817}{150}:\frac{1}{50}=\frac{-817}{3}\)

Ủng hộ tớ nha m.n?

Hãy tích cho tui đi

khi bạn tích tui

tui không tích lại bạn đâu

THANKS

1. a) Ta có: 2¹⁵⁰=(2³)⁵⁰=8⁵⁰

                   3¹⁰⁰=(3²)⁵⁰=9⁵⁰

Vì 8<9 nên 8⁵⁰<9⁵⁰

Hay 2¹⁵⁰<3¹⁰⁰

Vậy  2¹⁵⁰<3¹⁰⁰

Bài 1:

a) ta có: 2¹⁵⁰ = ( 2³)⁵⁰ = 8⁵⁰

3¹⁰⁰ = (3²)⁵⁰ = 9⁵⁰ > 8⁵⁰

=> 2¹⁵⁰ < 3¹⁰⁰

b) ta có: 3²⁴ = (3²)¹² = 9¹² < 16¹²

=> 3²⁴ < 16¹²

bài 2 thì bn tự tính ik

A = 2

- Ủng hộ -

CÓ ai giải giùm bài này đi , mình cũng có một bài tương tự mà chưa giải đc

\(a,\frac{2^3.2^4}{2^5}=\frac{2^7}{2^5}=2^2=4\)

\(b,\frac{\left(0,2\right)^5.\left(0,6\right)^4}{\left(0,2\right)^7.\left(0,3\right)^4}=\frac{\left(0,2\right)^5.\left(0,3\right)^4.2^4}{\left(0,2\right)^7.\left(0,3\right)^4}=\frac{2^4}{\left(0,2\right)^2}\)

\(c,\frac{3^3.12^4}{6^5.9^4}=\frac{3^3.6^4.2^4}{6^5.3^8}=\frac{2^4}{6.3^5}=\frac{2^4}{2.3.3^5}=\frac{2^3}{3^6}\)

\(d,\frac{2^3+2^4+2^5}{7^2}=\frac{8+16+32}{49}=\frac{56}{49}=\frac{8}{7}\)

\(e,\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}=\frac{2^{15}.3^8}{2^{15}.3^6}=3^2=9\)

còn CMR A=B nữa nhé