Ta có : x^4+2017x^2+2016x+2017

=x^4+x^3-x^3+x^2-x^2+2017x^2+2017x-x+2017

=x^4+x^3+x^2-x^3-x^2-x+2017x^2+2017x+2017

=x^2(x^2+x+1)-x(x^2+x+1)+2017(x^2+x+1)

=(x^2+x+1)(x^2-x+2017)

Nhớ k mk nha

Ta có : x^4+2017x^2+2016x+2017
=x^4+x^3-x^3+x^2-x^2+2017x^2+2017x-x+2017
=x^4+x^3+x^2-x^3-x^2-x+2017x^2+2017x+2017
=x^2(x^2+x+1)-x(x^2+x+1)+2017(x^2+x+1)
=(x^2+x+1)(x^2-x+2017)

chúc cậu hok tốt _@

x⁴+2017x²+2016x+2017

=(x²-x+2017)(x²+x+1)

đa thức <=> x⁴-x+2017x^2+2017x+2017=x(x^3-1)+2017(x^2+x+1)=x(x-1)(x^2+x+1)+2017(x^2+x+1)=(x^2+x+1)(x^2-x+2017)

Bạn phía trên làm sai rồi nhé

a,\(x^5-x^4-x^4+x^3+2x^3-2x^2-2x^2+2\)2x-2x+2\(x^4\left(x-1\right)-x^3\left(x-1\right)+2x^2\left(x-1\right)-2x\left(x-1\right)+2\left(x-1\right)\)

=\(\left(x^4-x^3+2x^2-2x+2\right)\left(x-1\right)\)

b,

câu b, c,d tương tự 

bạn tự làm nó nhé

bạn nhóm ba số giữa vs nhau r lấy x^4+1 xong phân k ra hehe mk cx ko chắc

bạn có: x^4 + 2016x^2 + 2015x + 2016
= x^4 + x^3 + x^2 - x^3 - x^2 - x + 2016x^2 + 2016x + 2016
= x^2(x^2 + x + 1) - x(x^2 + x + 1) + 2016(x^2 + x + 1)
= (x^2 + x + 1)(x^2 - x + 2016)

  \(x^4+2016x^2+2015x+2016\)

=\(x^4+x^3+x^2+2015x^2+2015x+2015+1-x^3\)

=\(x^2\left(x^2+x+1\right)+2015\left(x^2+x+1\right)+\left(1-x\right)\left(x^2+x+1\right)\)

=\(\left(x^2+x+1\right)\left(x^2+2015+1-x\right)\)

=\(\left(x^2+x+1\right)\left(x^2-x+2016\right)\)

2015x⁴ + 2016x² + x + 2016

= (2015x⁴ + 2015x³ + 2015x²) + (- 2015x³ - 2015x² - 2015x) + (2016x² + 2016x + 2016)

= (x² + x + 1)(2015x² - 2015x + 2016)

Vào câu trả lời tương tự đi có đáp án đó