1. (-6 - 2).(-6 + 2)=(-6 - 2)=-8;(-6 + 2)=-8

=>-8+-8=-16

2. (7.3-3) : (-6)=(7.3-3)=18 : (-6)=-3

3. (-5+9).(-4)=(-5+9)=4.(-4)=-16

4. 72:(-6.2+4)=72 : -8=-9

bấm máy tính hết là ra chứ j! 

tại sao câu 1 căn cứ vào đâu mà lại bằng (-6-2)

a ,   32 b ,   - 108 c ,   - 24

k minh minh giai

* (-6 - 2) . (-6 + 2)

=    -8   .     -4

=           32

*(7 . 3 - 3) : (-6)

=      18    : (-6)

=            -3

k cho mik nhe

(-6-2).(-6+2)

=-8.(-4)

=32

(7.3-3):(-6)

=(21-3):(-6)

=18:(-6)

=-3

(-5+9).(-4)

=4.(-4)

=-16

72:(-6.2+4)

=72.(-12+4)

=72.8

-3.7-4.(-5)+1

=-21+20+1

=-1+1

=0

18-10:(+2)-7

=18-5-7

=13-7

=6

15:(-5).(-3)-8

=-3.(-3)-8

=9-8

=1

(6.8-10:5)+3.(-7)

=(48-2)+3.(-7)

=46+(-21)

=25

1+1=2

a, (-6-2).(-6+2)

=(-6)²-2²

=36-4

=32

Mấy câu kia dễ mà bn tự lm nha

a, ( -6 - 2 ) . ( -6 + 2 )

= -8 . ( -4 )

= 32

Mấy câu kia tương tự

#hoc_tot#

\(a,\dfrac{6}{11}+6+\dfrac{5}{7}=\dfrac{42+462+55}{77}=\dfrac{559}{77}\)

\(b,\dfrac{9}{8}\times\dfrac{3}{12}:\dfrac{5}{9}=\dfrac{9}{8}\times\dfrac{3}{12}\times\dfrac{9}{5}=\dfrac{243}{480}=\dfrac{81}{160}\)

\(c,\dfrac{8}{7}:4+2=\dfrac{8}{7}\times\dfrac{1}{4}+2=\dfrac{8}{28}+2=\dfrac{2}{7}+2=\dfrac{16}{7}\)

\(d,\dfrac{3}{5}+4:\dfrac{6}{4}=\dfrac{3}{5}+4\times\dfrac{4}{6}=\dfrac{3}{5}+\dfrac{8}{3}=\dfrac{49}{15}\)

\(a,\dfrac{6}{11}+6+\dfrac{5}{7}=\dfrac{6}{11}+\dfrac{66}{11}+\dfrac{5}{7}=\dfrac{72}{11}+\dfrac{5}{7}=\dfrac{504}{77}+\dfrac{55}{77}=\dfrac{559}{77}\)

\(b,\dfrac{9}{8}\times\dfrac{3}{12}:\dfrac{5}{9}=\dfrac{9}{32}:\dfrac{5}{9}=\dfrac{9}{32}\times\dfrac{9}{5}=\dfrac{81}{160}\)

\(c,\dfrac{8}{7}:4+2=\dfrac{8}{7}\times\dfrac{1}{4}+2=\dfrac{2}{7}+2=\dfrac{2}{7}+\dfrac{14}{7}=\dfrac{16}{7}\)

\(d,\dfrac{3}{5}+4:\dfrac{6}{4}=\dfrac{3}{5}+4\times\dfrac{4}{6}=\dfrac{3}{5}+\dfrac{8}{3}=\dfrac{9}{15}+\dfrac{40}{15}=\dfrac{49}{15}\)

a,\(\frac{7}{10}\cdot\frac{4}{9}+\frac{3}{10}\cdot\frac{4}{9}-1\frac{7}{9}\)

\(=\frac{14}{45}+\frac{2}{15}-\frac{16}{9}\)

\(=\frac{14}{45}+\frac{6}{45}-\frac{80}{45}\)

\(=\frac{-60}{45}=\frac{-4}{3}\)

b,\(\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{5}{4}-\frac{2}{3}\right)\cdot\left(-3\right)^2+\frac{5}{9}\cdot30\%\)

\(=\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{7}{12}\right)\cdot9+\frac{5}{9}\cdot\frac{3}{10}\)

\(=\frac{-5}{6}+\frac{7}{3}+\frac{1}{6}\)

\(=\frac{-5}{6}+\frac{14}{6}+\frac{1}{6}\)

=\(=\frac{10}{6}=\frac{5}{3}\)