tìm x
a 5Xx-392=218
b(x +31)X 11 =6732:17
c(6Xx-39):7)X4=12
d3672:(119-(x-6)=36
a 5x X - 392=218
b (6 x X - 39 ): 7) x 4 = 12
c 3672 : ( 119 - ( X -6 ) = 36
a) 5. x -392 = 218
5.x =218+392
5.x = 610
x = 610 : 5
x= 122
b) [ ( 6 . x - 39 ) : 7] .4 = 12
(6.x-39 ) : 7 = 3
6.x-39= 21
6.x =21+39=60
x=10
c) 3672 : [ 119 - ( x - 6) ] =36
119-(x-6)= 3672:36=12
x-6 = 119- 12
x-6= 107
x= 107 + 6= 113
f/ 11x(X+2) = 5xX + 40
g/ 11x(X-6) = 4xX + 11
h/ (3xX - 4) : X + 10 = 12
k/ (5xX + 7) : X + 20 = 26
m/ Xx1999 - X = 1999x1997+1999
f) 11.(x+2)=5.x+40
=> 11x+22=5x+40
=> 6x=18
=> x=18:6=3
g)11.(x-6)=4.x+11
=> 11.x+(-66)=4x+11
=> 7x=77
=> x=77:7=11
h) (3x-4):x+10=12
=> 3x:x-4:x=12-10=2
=> 3-4:x=2
=> 4:x=3-2=1
=> x=4:1=4
k)(5x+7):x+20=26
=> 5x:x+7:x=26-20=6
=> 5+7:x=6
=> => 7:x=6-5=1
=> x=7:1=7
m) x.1999-x=1999.1997+1999
=> x.1998=1999.(1997+1)
=> x.1998=1999.1998
=> x=1999
**** cho mik nha Nguyễn Thị Thảo Ly
f/ 11x(X+2) = 5xX + 40
g/ 11x(X-6) = 4xX + 11
h/ (3xX - 4) : X + 10 = 12
k/ (5xX + 7) : X + 20 = 26
m/ Xx1999 - X = 1999x1997+1999
Đổi x thành a, ta có:
f. 11 x ( a + 2) = 5 x a + 40
11 x a + 11 x 2 = 5 x a + 40
11 x a + 22 = 5 x a + 40
6 x a + 5 x a + 22 = 5 x a + 40
6 x a + 22 = 40(Cùng bỏ 5 x a ở hai vế)
6 x a = 40 - 22
6 x a = 18
a = 18 : 6
a = 3
g. 11 x ( a - 6 ) = 4 x a + 11
11 x a - 11 x 6 = 4 x a + 11
4 x a + 7 x a - 66 = 4 x a + 11
7 x a - 66 = 11(Cùng bỏ đi 4 x a ở 2 vế)
7 x a = 11 + 66
7 x a = 77
a = 77 : 7
a = 11
h. ( 3 x a - 4 ) : a + 10 = 12
3 x a - 4 = ( 12 - 10 ) x a
3 x a - 4 = 2 x a
2 x a + a = 2 x a + 4
a = 4(Cùng bỏ đi 2 x a)
k. Tương tự h
m. a x 1999 - a = 1999 x 1997 + 1999
a x 1998 = 1999 x 1998
=> a = 1999
tìm x biết: (x + 1) + (x + 6) + (x + 11) + ... + (x + 31) + (x + 36) = 228
Số số hạng :
( 36 - 1) : 5 + 1 = 8 ( số hạng)
Tổng của dãy :
( 36 + 1) x 8 : 2 = 148
8x + 148 = 228
8x = 228 -148
8x =80
x = 80 : 8
x = 10
8x+(1+6+11+16+21+26+31+36)=228
8x+148=228
8x=228-148
8x=80
x=80/8
x=10
x+1+x+6+x+11+...+x+31+x36=228
8x+\(\frac{8\left(36+1\right)}{2}\)=228
8X+148=228
8x=80
x=10
tìm X
a, 2448 : [119-(X-6)]=24
b,(X-21) x 13 : 11=39
Tìm x biết: (x+1) + (x+6) + (x+11) +...+(x+31) + (x+36) = 228
Tìm x biết: (x+1) + (x+6) + (x+11) +...+(x+31) + (x+36) = 228
tính giá trị các biểu thức:
1) A=7/10 x11 + 7/11 x 12 + 7/12 x 13 + ...... +7/69 x 70
2)B= 1/25 x 27 + 1/ 27 x 29 + 1/29 x 31 + ... + 1/ 73 x 75
3) C= 4/2 x4 +4/4 x 6 + 4/6 x 8 + ... + 4/ 2008 x 2010
1) \(A=\frac{7}{10\times11}+\frac{7}{11\times12}+\frac{7}{12\times13}+...+\frac{7}{69\times70}\)
\(A=7\times\left(\frac{1}{10\times11}+\frac{1}{11\times12}+\frac{1}{12\times13}+...+\frac{1}{69\times70}\right)\)
\(A=7\times\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)
\(A=7\times\left(\frac{1}{10}-\frac{1}{70}\right)\)
\(A=7\times\frac{3}{35}\)
\(A=\frac{3}{5}\)
2) \(B=\frac{1}{25\times27}+\frac{1}{27\times29}+\frac{1}{29\times31}+...+\frac{1}{73\times75}\)
\(B=\frac{1}{2}\times\left(\frac{2}{25\times27}+\frac{2}{27\times29}+\frac{2}{29\times31}+...+\frac{2}{73\times75}\right)\).
\(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\times\frac{2}{75}\)
\(B=\frac{1}{75}\)
3) \(C=\frac{4}{2\times4}+\frac{4}{4\times6}+\frac{4}{6\times8}+...+\frac{4}{2008\times2010}\)
\(C=\frac{4}{2}\times\left(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{2008\times2010}\right)\)
\(C=2\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2008}-\frac{1}{2010}\right)\)
\(C=2\times\left(\frac{1}{2}-\frac{1}{2010}\right)\)
\(C=2\times\frac{502}{1005}\)
\(C=\frac{1004}{1005}\)
_Chúc bạn học tốt_
tìm số nguyên x
\(\left|x-14\right|+\left(-6\right)< -4\)
(-x +31) - 39 = -69 + 11
( -37 )-\(\left|7-x\right|\)= -127
(31-x)-39=11-69
31-x=11-69+39
31-x=-19
x=50
37+| 7-x | =127
|7-x | = 90
7-x=90 hoặc 7-x=-90
x=-81 hoắc x=97