x- 32:16=48

=>x-2=48

=>x=48+2

=>x=50

(x-32):16=48

=>x-32= 48x 16

=>x-32= 768

=>x=768+32

=>x=800

1.x=50

2.x=bấm máy tính nhá mik hơi bí chút

k ủng hộ nhá

1. x-32:16=48

         x-32=48.16

        x-32=768

            x=768+32

             x=800

Vậy x=800

2.(x-32):16=48

Tương tự như câu trên nha bn

*** mk nha

\(8x-2x+8=48\)

\(6x=48-8\)

\(6x=40\)

\(x=\frac{20}{3}\)

vậy \(x=\frac{20}{3}\)

x8 - x * 2 + 8 = 48

x.(8-2)=48-8

x.6=40

x=40/6=20/3

Chỗ x8 là sao??

x(x+1)-(x-1)(x+2)=8

\(\Leftrightarrow\)\(x^2+x-x^2-2x+x+2=8\)

\(\Leftrightarrow0x=6\left(ptvn\right)\)

\(\Rightarrow S=\varnothing\)

Ta có :

 \(x-\dfrac{8}{5}< -6\\ \Rightarrow x< -6+\dfrac{8}{5}\\ \Rightarrow x< -\dfrac{22}{5}=-4\dfrac{2}{5}\\ \Rightarrow-6< x< -1\dfrac{2}{5}\\ \Rightarrow x=-5\)

    Vậy...

\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{8}{5}< -6\\-6< x\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}x< -6+\dfrac{8}{5}\\x>-6\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}x< -\dfrac{22}{5}\\x>-6\end{matrix}\right.\\ \Rightarrow-6< x< -\dfrac{22}{5}\)

( 1 +8+ 2+3+..... +8+ 9+10 ) x( 6x8-48)

=(1+2+3+.......+8+9+10)x 48-48

=(1+2+3+.........+8+9+10)x0

= 0
^    ^ chúc bạn học tốt k cho mình nha

Bằng 0 nhé

what the hell?

\(...\Rightarrow x+x+\dfrac{x}{43}+\dfrac{x}{8}=14+148+\dfrac{10}{30}+\dfrac{5}{95}\)

\(\Rightarrow\left(1+1+\dfrac{1}{43}+\dfrac{1}{8}\right)x=162+\dfrac{1}{3}+\dfrac{1}{19}\)

\(\Rightarrow\left(\dfrac{2.43.8}{43.8}+\dfrac{1.8}{43.8}+\dfrac{1.43}{43.8}\right)x=\dfrac{162.3.19}{3.19}+\dfrac{1.19}{3.19}+\dfrac{1.3}{19.3}\)

\(\Rightarrow\left(\dfrac{688}{344}+\dfrac{8}{344}+\dfrac{43}{344}\right)x=\dfrac{9234}{57}+\dfrac{19}{57}+\dfrac{3}{57}\)

\(\Rightarrow\dfrac{739}{344}x=\dfrac{9256}{57}\)

\(\Rightarrow x=\dfrac{9256}{57}:\dfrac{739}{344}=\dfrac{9256}{57}.\dfrac{344}{739}=\dfrac{\text{3184064}}{\text{42123}}\)

\(\dfrac{x}{3}=\dfrac{y}{6}=\dfrac{2x^2}{18}=\dfrac{y^2}{36}=\dfrac{2x^2-y^2}{18-36}=\dfrac{-8}{-18}=\dfrac{4}{9}\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{4.3}{9}=\dfrac{4}{3}\\y=\dfrac{4.6}{9}=\dfrac{8}{3}\end{matrix}\right.\)

$\dfrac{x}{3}=-\dfrac{16}{48}\\\Leftrightarrow x=\dfrac{-16.3}{48}=-1$

$\dfrac{y}{-9}=-\dfrac{16}{48}\\\Leftrightarrow y=\dfrac{-16.(-9)}{48}=3$

$\dfrac{-8}{z}=\dfrac{-16}{48}\\\Rightarrow x=\dfrac{-8.48}{-16}=24$

Vậy $x=-1,y=3,z=24$

x=-1

y=-3

z=24