\(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}x\frac{4}{5}=15\frac{33}{17}\)

Theo mình thì VP = -5, vì nếu VP = 0 thì theo cách làm của mình x = \(\frac{-531}{23}\) (số to quá nên mình nghĩ là đề sai)

\(\frac{x+1}{4}-\frac{x+2}{5}+\frac{x+4}{7}-\frac{x+5}{8}+\frac{x+7}{10}-\frac{x+9}{12}=5\)

\(\Leftrightarrow\) \(\frac{x+1}{4}-1-\frac{x+2}{5}-1+\frac{x+5}{8}-1+\frac{x+7}{10}-1-\frac{x+9}{12}-1=0\)

\(\Leftrightarrow\) \(\frac{x-3}{4}-\frac{x-3}{5}+\frac{x-3}{8}+\frac{x-3}{10}-\frac{x-3}{12}=0\)

\(\Leftrightarrow\) (x - 3)(\(\frac{1}{4}-\frac{1}{5}+\frac{1}{8}+\frac{1}{10}-\frac{1}{12}\)) = 0

\(\Leftrightarrow\) x - 3 = 0

\(\Leftrightarrow\) x = 3

Vậy S = {3}

Chúc bn học tốt!!

câu c: ( ảnh kia câu c mình chụp chưa rõ nên chụp lại nhe) chữ nó xấu gì đâu:)

\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)

\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)

\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)

\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)

\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)

\(\Rightarrow-1\le x< 6\)

\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)

Bài b tương tự

bạn ơi bạn giải câu b được ko. mk ko biết làm câu b

con lon ct dg hong

\(\frac{3x-7}{5}=\frac{2x-1}{3}\)

\(\Leftrightarrow9x-21=10x-5\)

\(\Leftrightarrow-x=16\Leftrightarrow x=-16\)

\(\frac{4x-7}{12}-x=\frac{3x}{8}\)

\(\Leftrightarrow\frac{4x-7-12x}{12}=\frac{3x}{8}\)

\(\Leftrightarrow\frac{-7-8x}{12}=\frac{3x}{8}\)

\(\Leftrightarrow-56-64x=36x\)

\(\Leftrightarrow-56=100x\Leftrightarrow x=\frac{-14}{25}\)

\(\frac{x-2009}{1234}+\frac{x-2009}{5678}-\frac{x-2009}{197}=0\)

\(\Leftrightarrow\left(x-2019\right)\left(\frac{1}{1234}+\frac{1}{5678}-\frac{1}{197}\right)=0\)

Vì \(\left(\frac{1}{1234}+\frac{1}{5678}-\frac{1}{197}\right)\ne0\)nên x - 2019 = 0

Vậy x = 2019

\(\frac{5x-8}{3}=\frac{1-3x}{2}\)

\(\Leftrightarrow10x-16=3-9x\)

\(\Leftrightarrow19x=19\Leftrightarrow x=1\)

\(\frac{x-5}{6}-\frac{x-9}{4}=\frac{5x-3}{8}+2\)

\(\Rightarrow\frac{4x-20-6x+54}{24}=\frac{5x-3+16}{8}\)

\(\Rightarrow\frac{-2x+34}{24}=\frac{5x+13}{8}\)

\(\Rightarrow-16x-272=120x+312\)

\(\Leftrightarrow-136x=584\Leftrightarrow x=\frac{-73}{17}\)

Đây đâu phải toán lớp một mà là toán lớp 6 thì có

Erza

a) \(\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{18}{30}-\frac{10}{30}-\frac{5}{30}=\frac{18-10-5}{30}=\frac{1}{10}\)

b) \(\frac{4}{7}\times\frac{5}{8}\times\frac{7}{12}=\frac{4\times5\times7}{7\times8\times12}=\frac{140}{672}=\frac{5}{24}\)

c) \(\frac{25}{28}\div\frac{15}{14}\times\frac{6}{7}=\frac{25}{28}\times\frac{14}{15}\times\frac{6}{7}=\frac{25\times14\times6}{28\times15\times7}=\frac{2100}{2940}=\frac{5}{7}\)

                    Thấy đúg thì tk nha các bn !!

a,3/5 - 1/3 - 1/6

= 4/9 - 1/6

= 5/9

b,4/7x5/8x7/12

= 5/14 x 7/12

= 5/24

c,25/18 :15/14 x 6/7

= 25/28 x 14/15 x 6/7

= 5/6 x 6/7

= 5/7

\(\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{18}{30}-\frac{10}{30}-\frac{5}{30}=\frac{3}{30}=\frac{1}{10}\)

\(\frac{4}{7}\cdot\frac{5}{8}\cdot\frac{7}{12}=\frac{4\cdot5\cdot7}{7\cdot8\cdot12}=\frac{1\cdot5}{8\cdot3}=\frac{5}{24}\)

\(\frac{25}{28}:\frac{15}{14}\cdot\frac{6}{7}=\frac{25}{28}\cdot\frac{14}{15}\cdot\frac{6}{7}=\frac{25\cdot14\cdot6}{28\cdot15\cdot7}=\frac{5}{7}\)