phan tich cac da thuc thanh nhan tu
-x - y^2 + x^2 -y
phan tich thanh cac nhan tu da thuc
x^2-25+y+2xy
phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
con bai 32, 33 neu ban tra loi duoc minh h them
phan tich cac da thuc sau thanh nhan tu:
(y^2+Y)^2 -9y^2 - 9y+20
(X+3)*(x+6)*(x+9)*(x+12)+81
dat y^2+y=z cho gon
\(z^2-9z+20=z^2-4z-5z+20=z\left(z-4\right)-5\left(z-4\right)=\left(z-4\right)\left(z-5\right)\)
\(thaylai:\left(y^2+y-4\right)\left(y^2+y-5\right)\)
Phan tich cac da thuc thanh nhan tu:
x3- 2x2 - x + 2
x2 + 6x - y2 + 9
x^3-2x^2-x+2=x^2(x-2)-(x-2)=(x^2-1)(x-2)=(x-1)(x+1)(x-2)
a)(x3- x) - (2x2 - 2)
= x (x2 - 1) - 2 (x2 - 1)
= (x - 2) (x2-1)
a) \(x^3-2x^2-x+2=\left(x^3-x\right)+\left(-2x^2+2\right)\)
\(=x\left(x^2-1\right)-2\left(x^2-1\right)=\left(x-2\right)\left(x^2-1\right)=\left(x-2\right)\left(x+1\right)\left(x-1\right)\)
b) \(x^2+6x-y^2+9=\left(x^2+6x+9\right)-y^2\)
\(\left(x+3\right)^2-y^2=\left(x+3-y\right)\left(x+3+y\right)\)
phan tich da thuc thanh nhan tu
x^2-3x+3y-y^2
x2 - 3x + 3y - y2
= (x2 - y2) - (3x - 3y)
= (x - y)(x + y) - 3(x - y)
= (x - y)(x + y - 3)
= x2 - y2 - 3x+3y = (x-y)(x+y) -3(x-y)
= (x+y+3)(x-y)
nhớ chọn cho mk nha!!!!!!
Phan tich da thuc x^2 + y^3 + 2x^2 -2cy + 2y^2 thanh nhan tu
phan tich da thuc thanh nhan tu
x^2+y^2+z^2+3xyz
Phan tich da thuc thanh nhan tu
(xy-1)^2 -x^2-y^2
Phan tich da thuc thanh nhan tu
x^2 + y^2 + z^2 - 3xyz