|3x-1|=7/6

=>3x-1=-7/6 hoặc 7/6

=>3x=-1/6

=>x=-1/18

=>3x=13/6

=>x=13/18

b)5/3*|x-1/2|+1/3=4/3

=>5/3*|x-1/2|=1

=>|x-1/2|=3/5

=>x-1/2=-3/5 hoặc 3/5

=>x=-1/10

=>x=11/10

\(\left|x-3,4\right|+\left|2,6-x\right|=0\\ \Leftrightarrow\left\{{}\begin{matrix}x-3,4=0\\2,6-x=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=3,4\\x=2.6\left(vô.lí\right)\end{matrix}\right.\)

1424579

Ta có: |x| = x+1

\(\Rightarrow\orbr{\begin{cases}x=-\left(x+1\right)\\x=x+1\end{cases}}\Rightarrow\orbr{\begin{cases}2x=-1\\0=1\left(loai\right)\end{cases}}\)

=> 2x = -1

=> x = -1/2

Vậy: x = -1/2

Z = { -2 ; -1 ; 0 ; 1 ; 2 ; 3 ; 4 ; 5 ; 6 ; 7 ; 8 ; 9}

Ta có /x-8/+/y+2/=2

=>\(\hept{\begin{cases}x-8=1\\y+2=1\end{cases}}\)

hay\(\hept{\begin{cases}x-8=2\\y+2=0\end{cases}}\)

hoặc\(\hept{\begin{cases}x-8=0\\y+2=2\end{cases}}\)

suy ra\(\hept{\begin{cases}x=9;10;8\\y=-1;-2;0\end{cases}}\)

nhớ tk nha

\(2x\left|x-1\right|+5x\left|x-1\right|-8x\left|x-1\right|=7\)

\(\left|x-1\right|.\left(2x+5x-8x\right)=7\)

\(\left|x-1\right|.\left(-x\right)=7\)

\(\left|x-1\right|=\frac{-7}{x}\) ( với \(x\ne0\))

5 hoặc -5

|-125| - |x|

|x| = (-6).(-20)

|x| = 120

|-125| - |-120|

= 125 - 120

= 5

l-125l-lxl = (-6).(-20)

l-125-xl = 120

TH1:  -125-x=120=> -x = 120+125 = 245

  => x= -245

TH2: -125-x=-120=> -x = -120+125= 5

 => x = -5