tim x biet x^2015=1^x
tim x biet (x-2015)2015=1
tim x nguyen biet /x-1/^2+(x-1)^2=2015./x-1/
tim x
giup dum
tim x biet (x-1)^2017=4*(x-1)^2015
(x - 1)2017 = 4(x - 1)2015
=> (x - 1)2017 - 4(x - 1)2015 = 0
=> (x - 1)2015.(x - 1)2 - 4(x - 1)2015 = 0
=> (x - 1)2015.[(x - 1)2 - 4] = 0
=> (x - 1)2015 = 0 hoặc (x - 1)2 - 4 = 0
=> x - 1 = 0 hoặc (x - 1)2 = 4
=> x = 1 hoặc x - 1 = 2 hoặc x - 1 = -2
=> x = 1 hoặc x = 3 hoặc x = -1
Vậy x = {-1;1;3}
(x-1)^2017=4*(x-1)^2015
(x-1)^2017/(x-1)^2015=4
(x-1)^2=4
(x-1)=2 hoặc -2
giải tiếp....................
(x - 1)2017 = 4.(x - 1)2015
=> (x - 1)2017 - 4(x - 1)2015 = 0
=> (x - 1)2015.(x - 1)2 - 4(x - 1)2015 = 0
=> (x - 1)2015.[(x - 1)2 - 4] = 0
=> \(\orbr{\begin{cases}\left(x-1\right)^{2015}=0\\\left(x-1\right)^2-4=0\end{cases}}\)=>\(\orbr{\begin{cases}x-1=0\\\left(x-1\right)^2=4=2^2\end{cases}}\)
=> \(\orbr{\begin{cases}x=1\\x-1=2\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=3\end{cases}}}\)
Vậy x = {1;3}
tim x biet
b, (x-1)^2010=(x-1)^2015
a,TH1:x+2=0
x =0-2
x =-2
TH2:x^2-64=0
x^2 =0+64
x^2 =64
Mà : x^2 =8^2
Vay x=8
cau b ko bt
Tim x la so tu nhien, biet:
x - 4/2015 - 1/2015 = 10 - 2x
tim x biet /x-2015/=1
Nhớ nhấn đúng cho mình nhé Lê Nguyễn Thúy Vi
/ x - 2015 / =1
\(\Rightarrow\int^{x-2015=-1}_{x-2015=1}\)
\(\Rightarrow\int^{x=-1+2015=2014}_{x=1+2015=2016}\)
1. Tim x biet : \(2015-\left|x-2015\right|=x;\left|x\right|=-x-5\)
2015-|x-2015|=x
=>|x-2015|=2015-x
=>|x-2015=-(x-2015)
=>x-2015 < 0
=>x < 2015
ko chắc nữa
Tim x biet x-1/2015 + x-2/2014= x-3/2013 + x-4/2012
=>(x-1)/2015 - 1 + (x-2(/2014 -1 = (x-3)/2013 -1 + (x-4)/2012 -1
=>(x-2016)*(1/2015+1/2014-1/2013-1/2012)=0
=>x=2016
Trừ 1 ở mỗi p/s,ta có:
\(\left(\frac{x-1}{2015}-1\right)+\left(\frac{x-2}{2014}-1\right)=\left(\frac{x-3}{2013}-1\right)+\left(\frac{x-4}{2012}-1\right)\)
\(\Leftrightarrow\left(\frac{x-2016}{2015}\right)+\left(\frac{x-2016}{2014}\right)=\left(\frac{x-2016}{2013}\right)+\left(\frac{x-2016}{2012}\right)\)
\(\Leftrightarrow\frac{x-2016}{2015}+\frac{x-2016}{2014}-\frac{x-2016}{2013}-\frac{x-2016}{2012}=0\)
\(\Leftrightarrow\left(x-2016\right)\left(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\right)=0\)
Vì \(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\ne0\)
=>x-2016=0
=>x=2016
Vậy..................
mình hỏi bài này :tìm số tự nhiên x biết :(x-2)^2014=(x-2)^2016
Tim STN x, y biet:
a,25y+15x=126
b, 2016x-1=y-2015-|y-2015|