\(\left(x+y\right)^3-\left(x-y\right)^3=x^3+3x^2y+3xy^2+y^3-x^3+3x^2y-3xy^2+y^3=6x^2y+2y^3\)

Vietnam =))

I'd like to visit New York in United States of America OR London in United Kingdom

First I will find you new.

(Ý kiến riêng )

đây bản dịch : Khi bạn đến một đất nước mới, bạn muốn làm gì đầu tiên?

When I come to a country I will learn about the culture and language of that country

- Bạn ơi bài này bạn đăng nhiều lần rồi, bạn đăng thêm làm gì nữa?

- Với lại hình như có người trả lời cho bạn rồi mà?

Vietnam is a wonderful country located in Southeast Asia. The impact of the Western wave on culture has slowed somewhat where it has changed many things. So if a brother or a foreign friend came to Vietnam, would you introduce him to what to do in Vietnam?

In my opinion, here are some things to do when coming to Vietnam:

1. KARAOKE SING

2. at HOMESTAY

dealine tết đk , hỉu quá mà

Bạn tham khảo bài của chị Tuệ Lâm làm nhé!!

Dear Glory,

Vietnam is a wonderful country located in Southeast Asia. The impact of the Western wave on culture has slowed somewhat where it has changed many things. So if a brother or a foreign friend came to Vietnam, would you introduce him to what to do in Vietnam?

In my opinion, here are some things to do when coming to Vietnam:

1. KARAOKE SING

2. at HOMESTAY

3,VISIT SON MY RULES4,EXPERIENCE Phong Nha - Ke Bang National Parkit's great, come to vietnam my country, i will take you to many places. That promise

                                                                                                      Friend,

                                                                                    < Ghi tên của bạn vào đây nha! >

tr oi có 4 câu em ko cần tách đou cj lm r đó

Many people using cars and motobikes nowadays, however they have a lot of smoke into the air.  It cause air polluted and have much bad effects on people

Fix: pollution

\(\dfrac{x+2}{x-3}+\dfrac{x-2}{x}=\dfrac{x^2+2x+6}{x\left(x-3\right)}\)  đkxđ: x khác 3 , x khác 0

\(\Leftrightarrow\dfrac{x\left(x+2\right)}{x\left(x-3\right)}+\dfrac{\left(x-2\right)\left(x-3\right)}{x\left(x-3\right)}-\dfrac{x^2+2x+6}{x\left(x-3\right)}=0\)

\(\Leftrightarrow\dfrac{x^2+2x}{....}+\dfrac{x^2-3x-2x+6}{.....}-\dfrac{x^2+2x+6}{...}=0\)

\(\Leftrightarrow x^2+2x+x^2-3x-2x+6-x^2-2x-6=0\)

\(\Leftrightarrow x^2-5x=0\)

\(\Leftrightarrow x\left(x-5\right)=0\)

\(\Rightarrow\left\{{}\begin{matrix}x=0\left(tm\right)\\x=5\left(tm\right)\end{matrix}\right.\)

đk : x khác -3 ; 3

\(\Rightarrow\left(x+3\right)^2-4x^2=\left(x-3\right)^2\Leftrightarrow-3x^2+6x+9=x^2-6x+9\)

\(\Leftrightarrow4x^2-12x=0\Leftrightarrow4x\left(x-3\right)=0\Leftrightarrow x=3\left(ktm\right);x=0\)

\(\dfrac{x+3}{x-3}-\dfrac{4x^2}{x^2-9}=\dfrac{x-3}{x+3}\) đkxđ: x khác 3 ; x khác -3

\(\Leftrightarrow\dfrac{x+3}{x-3}-\dfrac{4x^2}{\left(x-3\right)\left(x+3\right)}-\dfrac{x-3}{x+3}=0\)

\(\Leftrightarrow\dfrac{\left(x+3\right)\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}-\dfrac{4x^2}{\left(x-3\right)\left(x+3\right)}-\dfrac{\left(x-3\right)\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}=0\)

\(\Leftrightarrow\dfrac{x^2+6x+9}{...}-\dfrac{4x^2}{.....}-\dfrac{x^2-6x+9}{....}=0\)

\(\Leftrightarrow x^2+6x+9-4x^2-x^2+6x-9=0\)

\(\Leftrightarrow-4x^2+12x=0\)

\(\Leftrightarrow-4x\left(x-3\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=0\left(tm\right)\\x=3\left(kotm\right)\end{matrix}\right.\)

Vậy tập nghiệm của pt có S thuộc \(\left\{0\right\}\)