2x+5+3^4.3^2
Tìm x,biết
A) (-3)^2x=9^5
B) 9.5^ x-3=6.5^6+3.5^6
C) 5^x+4-3.5^x+3=5^11.2
D) 3^x+2+4.3^x+1=7.3^6
E) 5^x+3=10^5.6^3:4^4.3^3
\(3\left(4-x\right)-5\left(2-2x\right)=4.3^2-16.2^2\)
\(3\left(4-x\right)-5\left(2-2x\right)=4.3^2-16.2^2\)
\(12-3x-10+10x=2^2.3^2-2^4.2^2\)
\(2+7x=-28\)
\(7x=-30\)
\(x=\frac{-30}{7}\)
bài 3 tìm x thuộc N
a. 4.(x-5)-2 mũ 3 = 2 mũ 4.3
b, 4. x mũ 3 + 15 = 271
(2x -3) mũ 2 = 169
Bài 3 :
a) 4.(x-5) - 2 3=24.3
4x-20-8=48
4x=76
x=19
b) 4.x3+15=271
4.x3=256
x3=64
=> x=4
c) ( 2x-3)2= 169
=> 2x-3= 13
2x=16
x=8
Chúc bạn học tốt !
4*(x-5) - 2^3 = 2^4*3
4*(x-5) - 8 = 16*3
4*(x-5) - 8 = 48
4*(x-5) = 48 + 8
4*(x-5) = 56
x- 5 = 56 : 4
x - 5 = 14
x = 14 + 5
x = 19
4*x^3 + 15 = 271
4*x^3 = 271 - 15
4*x^3 = 256
x^3 = 256 : 4
x^3 = 64
x^3 = 4^3
x = 4
5⁶ : 5³ +2³ :2²
3333 : 3 + 225 :15
15.2³ + 4.3² - 5.7
5.4² - 18 :3²
6² : 4.3 +2.5²
80 - ( 4.5² -3.2³)
Tính
5⁶ : 5³ +2³ :2²
3333 : 3 + 225 : 15
15 . 2³ + 4.3² -5.7
5.4² - 18 : 3²
6² : 4.3 + 2.5³
80 - ( 4.5² - 3.2³)
Lời giải:
a.
$=5^{6-3}+2^{3-2}=5^3+2^1=125+2=127$
b.
$=3333:3+225:15=1111+15=1126$
c.
$=15.2^3+4.3^2-5.7=15.8+4.9-35=120+36-35=120+1=121$
d.
$=5.4^2-18:3^2=5.16-18:9=80-2=78$
e.
$=6^2:4.3+2.5^3=36:4.3+2.125$
$=9.3+250=27+250=277$
f.
$=80-(4.25-3.8)=80-(100-24)=80-100+24=-20+24=4$
Tính
5⁶ : 5³ +2³ :2²
3333 : 3 + 225 : 15
15 . 2³ + 4.3² -5.7
5.4² - 18 : 3²
6² : 4.3 + 2.5³
80 - ( 4.5² - 3.2³)
rút gọn biểu thức: (27^10-5.81^4.3^12+4.9^8.3^8):41.3^24
giải phương trình: 4x^2-9-(2x+3)(2x-1)=0
x^3+x^2-4x=4
x^2(x^2+4)-x^2-4=0
(3x-3)^2=(x+5)^2
(2x-3)^2==(x+5)^2
x^2(x-1)-(4x^2+8x-4)=0
Giải phương trình:
\(4x^2-9-\left(2x+3\right)\left(2x-1\right)=0\)
\(\Leftrightarrow\left(2x-3\right)\left(2x+3\right)-\left(2x+3\right)\left(2x-1\right)=0\)
\(\Leftrightarrow\left(2x+3\right)\left(2x-3-2x+1\right)=0\)
\(\Leftrightarrow\left(2x-3\right).\left(-2\right)=0\)
\(\Leftrightarrow2x-3=0\)
\(\Leftrightarrow x=\dfrac{-3}{2}\)
Vậy nghiệm của phương trình là \(x=\dfrac{-3}{2}\) .
\(x^3+x^2-4x=4\)
\(\Leftrightarrow x^3+x^2-4x-4=0\)
\(\Leftrightarrow x^2\left(x+1\right)-4\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x^2-4\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-2\right)\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=0\\x-2=0\\x+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=2\\x=-2\end{matrix}\right.\)
Vậy tập nghiện của phương trình là S= { -2; -1; 2}.
\(x^2\left(x^2+4\right)-x^2-4=0\)
\(\Leftrightarrow x^2\left(x^2+4\right)-\left(x^2+4\right)=0\)
\(\Leftrightarrow\left(x^2+4\right)\left(x^2-1\right)=0\)
\(\Leftrightarrow x^2-1=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x+1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)
Vậy phương trình có tập nghiệm là S= {-1; 1}.
\(\left(3x-3\right)^2=\left(x+5\right)^2\)
\(\Leftrightarrow\left(3x-3\right)^2-\left(x+5\right)^2=0\)
\(\Leftrightarrow\left(3x-3-x-5\right)\left(3x-3+x+5\right)=0\)
\(\Leftrightarrow\left(2x-8\right)\left(4x+2\right)=0\)
\(\Leftrightarrow2\left(x-4\right).2\left(2x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\2x+1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=\dfrac{-1}{2}\end{matrix}\right.\)
Vậy phương trình có tập nghiệm là S\(=\left\{\dfrac{-1}{2};4\right\}\) .
\(\left(2x-3\right)^2=\left(x+5\right)^2\)
\(\Leftrightarrow\left(2x-3\right)^2-\left(x+5\right)^2=0\)
\(\Leftrightarrow\left(2x-3-x-5\right)\left(2x-3+x+5\right)=0\)
\(\Leftrightarrow\left(x-8\right)\left(3x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-8=0\\3x+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=\dfrac{-2}{3}\end{matrix}\right.\)
Vậy phương trình có tập nghiệm là S\(=\left\{\dfrac{-2}{3};8\right\}\) .
\(x^2\left(x-1\right)-\left(4x^2+8x-4\right)=0\)
\(\Leftrightarrow x^2\left(x-1\right)-4\left(x^2+2x-1\right)=0\)
\(\Leftrightarrow x^2\left(x-1\right)-4\left(x-1\right)^2=0\)
\(\Leftrightarrow\left(x-1\right)\left[x^2-4\left(x-1\right)\right]=0\)
\(\Leftrightarrow\left(x-1\right)\left(x^2-4x+4\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(x-2\right)^2=0\)
\(\Leftrightarrow x-1=0\)
\(\Leftrightarrow x=1\)
Vậy nghiệm của phương trình là x=1.
(\(27^{10}-5.81^4.3^{12}+4.9^8.3^8\)):\(\left(41.3^{24}\right)\)
\(=\left[\left(3^3\right)^{10}-5.\left(3^4\right)^4.3^{12}+4.\left(3^2\right)^8.3^8\right]:\left(41.3^{24}\right)\)
\(=\left(3^{30}-5.3^{28}+4.3^{24}\right):\left(41.3^{24}\right)\)
\(=\left[3^{24}\left(3^6-5.3^4+4\right)\right]:\left(41.3^{24}\right)\)
\(=\left(3^{24}.328\right):\left(41.3^{24}\right)\)
\(=328:41=8\)
Tìm x ,biết
a)1440:[41-(2x-5)]=2^4.3
b)5.[225-(x-10)]-125=0
c)6: (chia hết) x
d)|x|=|-3|
e)2|x|+(-5)=7
a) 1440: [41-{2x-5}]=16.3
41-(2x-5)=1440-48
41-(2x-5)=1392
2x-5=41-1392
2x-5=-1351
2x=-1351+5
2x=-1346
x=(-1346):2
x=-673
b) 5.[225-(x-10)]-125=0
5.[225-(x-10)=0+125
225-(x-10)=125:5
225-(x-10)=25
x-10=225-25
x-10=200
x=200+10
x=210
tim x
a)2x3-25=29
b)125:(3x-10)=25
c)136-(2x-4)=32.2
d)140:(15-x)=70
e)4.3x-1=35
g)360-(220-4x)=160
f)24:22+x.33.3=166
h)4(x-5)-25=75
i)35-5(2x+2)=5
k)2x3-126=2