Ai làm đc giải cụ thể ra nha!thanks

1 + 1/3 + 1/6 + 1/10 + .......... + 1/x.(x+1):2 =1 + 1991/1993

1/2.(1 + 1/3 + 1/6 + 1/10+........+ 1/x.(x+1):2=3984/3986

1/2 + 1/6 +1/12 + .......... +1/x.(x+1)=3984/3986

1/1.2 + 1/2.3 + 1/3.4 +..........+.1/x.(x+1)=3984/3986

2-1/1.2 + 3-2/2.3 + 4-3/3.4 +..........+ x + 1 - x/x.(x+1)

1-1/2+1/2-1/3+1/3-1/4+..........+1/x -1/x+1 =3984/3986

1-1/x+1=3984/3986

   1/x+1=1-3984/3986

   1/x+1=2/3986=1/1993

x+1=1993

x    =1993-1

x    =1992

cảm ơn

cảm ơn nhé thế là bai về nhà mình đã giải quyết xong 

a)\(\frac{1}{5\cdot8}+\frac{1}{8\cdot11}+...+\frac{1}{x\left(x+3\right)}=\frac{101}{1540}\)

\(\Leftrightarrow\frac{1}{3}\left(\frac{3}{5\cdot8}+\frac{3}{8\cdot11}+...+\frac{3}{x\left(x+3\right)}\right)=\frac{101}{1540}\)

\(\Leftrightarrow\frac{1}{3}\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}\right)=\frac{101}{1540}\)

\(\Leftrightarrow\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}\)\(\Leftrightarrow\frac{1}{x+3}=\frac{1}{308}\)

\(\Leftrightarrow x+3=308\Leftrightarrow x=305\)

b ko hiểu đề