\(\left(2x-14\right):12=26\)

\(2x-14=26.12\)

\(2x-14=312\)

\(2x=312+14\)

\(2x=326\)

\(x=326:2\)

\(x=163\)

2x-14=26*12

2x-14=312 

2x=312-14

2x=298

x= 298:2

x=149

x = 163

1)\(x=\left(\dfrac{1}{5}+\dfrac{2}{3}\right):\dfrac{4}{7}=\left(\dfrac{3}{15}+\dfrac{10}{15}\right):\dfrac{4}{7}=\dfrac{13}{15}:\dfrac{4}{7}=\dfrac{91}{60}\)

2)\(x=\left(-\dfrac{3}{10}-\dfrac{3}{4}\right):\dfrac{1}{2}=\left(-\dfrac{6}{20}-\dfrac{15}{20}\right):\dfrac{1}{2}=-\dfrac{21}{20}:\dfrac{1}{2}=-\dfrac{21}{10}\)

3)\(x=-\dfrac{24}{36}-\dfrac{7}{15}=-\dfrac{2}{3}-\dfrac{7}{15}=\dfrac{-10}{15}-\dfrac{7}{15}=-\dfrac{17}{15}\)

1) \(\dfrac{4}{7}x=\dfrac{1}{5}+\dfrac{2}{3}\)

\(\dfrac{4}{7}x=\dfrac{13}{15}\)

\(x=\dfrac{91}{60}\)

2) \(\dfrac{1}{2}x=-\dfrac{3}{10}-\dfrac{3}{4}\)

\(\dfrac{1}{2}x=-\dfrac{21}{20}\)

\(x=-\dfrac{21}{10}\)

3) \(x=-\dfrac{24}{36}-\dfrac{7}{15}\)

\(x=\dfrac{-2}{3}+\dfrac{7}{15}\)

\(x=-\dfrac{17}{15}\)

1) 4/7 x - 2/3 = 1/5

4/7 x = 1/5 + 2/3

4/7 x = 13/15

x = 13/15 : 4/7

x = 91/60

2)1/2 x + 3/4 = -3/10

1/2 x = -3/10 - 3/4 

1/2 x = -21/20

x = -21/20 : 1/2

x = -21/10

3)x+7/15 = -24/36

x+7/15 = -2/3

x = -2/3 - 7/15

x = -17/15.

\(\left(2x-6\right)\times\left(5-x\right)=0\)

\(2x-6=0;5-x=0\)

\(x=3;x=5\)

Vậy: \(x=3;x=5\)

$\left(2x-6\right)\times \left(5-x\right)=0$

$2x-6=0;5-x=0$

$x\; =3,\; x\; =\; 5$

Vậy x = 3 và 5.

Lời giải:

Lần sau bạn nhớ ghi đầy đủ đề. $ABC$ là tam giác vuông tại $A$.

$\frac{AB}{AC}=\frac{3}{4}$

$\Rightarrow AC=\frac{4AB}{3}=\frac{4.15}{3}=20$ (cm)

Áp dụng định lý Pitago:

$y=BC=\sqrt{AB^2+AC^2}=\sqrt{15^2+20^2}=25$ (cm) 

$S_{ABC}=AB.AC:2=AH.BC:2$

$\Rightarrow AB.AC=AH.BC$

$\Rightarrow x=AH=\frac{AB.AC}{BC}=\frac{15.20}{25}=12$ (cm)

mk ko biet

1) 4⁶

2) 4⁶⁰ 

3) 8¹⁶

4) 16¹⁰

5) 32⁸

`a)(4,5-2x)*1 4/7=11/14`

`=>(4,5-2x)*11/7=11/14`

`=>4,5-2x=1/2`

`=>2x=4,5-0,5=4`

`=>x=2`

Vậy `x=2`

`b)(2,8x-32):2/3=-90`

`=>2,8x-32=-90*2/3=-60`

`=>2,8x=-28`

`=>x=-10`

Vậy `x=-10`

\(a,=x\left(x^2-x-12\right)=x\left(x^2-4x+3x-12\right)\\ =x\left(x-4\right)\left(x+3\right)\\ b,=x\left(x+7\right)\)

a) \(x^3-x^2-12x=x\left(x^2-x-12\right)=x\left(x-4\right)\left(x+3\right)\)

b) \(x^2+7x=x\left(x+7\right)\)

a) \(\dfrac{49}{81}=\dfrac{7^x}{9^x}\)(sửa đề)

\(\Leftrightarrow\left(\dfrac{7}{9}\right)^2=\left(\dfrac{7}{9}\right)^x\)\(\Rightarrow x=2\)

b) \(\dfrac{-64}{343}=\left(-\dfrac{4^x}{7^x}\right)\)(sửa đề)

\(\Leftrightarrow\left(-\dfrac{4}{7}\right)^3=\left(-\dfrac{4}{7}\right)^x\) \(\Rightarrow x=3\)

c) \(\dfrac{9}{144}=\dfrac{3^x}{12^x}\)(sửa đề)

\(\Leftrightarrow\left(\dfrac{3}{12}\right)^2=\left(\dfrac{3}{12}\right)^x\Rightarrow x=2\)

d) \(-\dfrac{1}{32}=\left(-\dfrac{1^x}{2^x}\right)\)(sửa đề)

\(\Leftrightarrow\left(-\dfrac{1}{2}\right)^5=\left(-\dfrac{1}{2}\right)^x\Rightarrow x=5\)

Mong bạn xem lại đề bài.

\(a,\left(x-15\right)\times7-270=169\times45\\ \left(x-15\right)\times7-270=7605\\ \left(x-15\right)\times7=7605+270\\ \left(x-15\right)\times7=7875\\ x-15=7875:7\\ x-15=1125\\ x=1125+15\\ x=1140\\ b,64-\left(34\times x-8\right)=4\\ 34\times x-8=64-4\\ 34\times x-8=60\\ 34\times x=60+8\\ 34\times x=68\\ x=68:34\\ x=2\)