Tìm x
a, 1+2+3+...+x = 1275
b,(x+1)+(x+2)+(x+3)+...+(x+99)=6138
c,x*1+x*2+x*3+...+x*99= 495
NT
Những câu hỏi liên quan
1/1 x 10 + 1/2 x 15 + 1/3 x 20+...........................................+1/98 x 495 + 1/99 x 500
tính giá trị của tổng sau :
1/1 x 10 + 1/2 x 15 + 1/3 x 20 + ... + 1/89 x 495 + 1/ 99 x 500
\(\frac{1}{1\times10}+\frac{1}{2\times15}+\frac{1}{3\times20}+...+\frac{1}{98\times495}+\frac{1}{99\times500}\)
\(=\frac{1}{1\times2\times5}+\frac{1}{2\times3\times5}+\frac{1}{3\times4\times5}+...+\frac{1}{98\times99\times5}+\frac{1}{99\times100\times5}\)
\(=\frac{1}{5}\times\left(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{98\times99}+\frac{1}{99\times100}\right)\)
\(=\frac{1}{5}\times\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)
\(=\frac{1}{5}\times\left(1-\frac{1}{100}\right)=\frac{1}{5}\times\frac{99}{100}=\frac{99}{500}\)
\(\frac{1}{1\times10}+\frac{1}{2\times15}+\frac{1}{3\times20}+...+\frac{1}{98\times495}+\frac{1}{99\times500}\)
\(=\frac{1}{1\times2\times5}+\frac{1}{2\times3\times5}+\frac{1}{3\times4\times5}+...+\frac{1}{98\times90\times5}+\frac{1}{90\times100\times5}\)
\(=\frac{1}{5}\times\left(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{98\times99}+\frac{1}{99\times100}\right)\)
\(=\frac{1}{5}\times\left(\frac{2-1}{1\times2}+\frac{3-2}{2\times3}+...+\frac{99-98}{98\times99}+\frac{100-99}{99\times100}\right)\)
\(=\frac{1}{5}\times\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)
\(=\frac{1}{5}\times\left(1-\frac{1}{100}\right)=\frac{99}{500}\)
cảm ơn bạn Xyz và bạn Đoàn Đức Hà nhìu (^-^) thank you !!!!!!!!!!!!!!!!!
Tìm x bt:
a) x-1/99 + x-2/98 + x-3/97 + x-4/96 = 4
b) x+1/99 + x+2/98 + x+3/97 = 3
c) x-1/99 + x-2/49 + x-4/32 = 6
Giúp mik với! Th5 mik mới nộp nhưng mong các bn giúp mik!
a) \(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-3}{97}+\frac{x-4}{96}=4\)
\(\Rightarrow\frac{x-1}{99}-1+\frac{x-2}{98}-1+\frac{x-3}{97}-1+\frac{x-3}{96}-1=4-4\)
\(\Rightarrow\frac{x-100}{99}+\frac{x-100}{98}+\frac{x-100}{97}+\frac{x-100}{96}=0\)
\(\Rightarrow\left(x-100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)
\(\Rightarrow x-1=0\) ( vì \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\ne0\) )
Vậy x = 1
b) \(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}=3\)
\(\Rightarrow\frac{x+1}{99}+1+\frac{x+2}{98}+1+\frac{x+3}{97}+1=3-3\)
\(\Rightarrow\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}=0\)
\(\Rightarrow\left(x+100\right).\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}\right)=0\)
Vì \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}\ne0\)
=> x + 100 = 0
=> x = -100
c) \(\frac{x-1}{99}+\frac{x-2}{49}+\frac{x-4}{32}=6\)
\(\Rightarrow\frac{x-1}{99}-1+\frac{x-2}{49}-2+\frac{x-4}{32}-3=6-6\)
\(\Rightarrow\frac{x-100}{99}+\frac{x-100}{49}+\frac{x-100}{32}=0\)
\(\Rightarrow\left(x-100\right)\left(\frac{1}{99}+\frac{1}{49}+\frac{1}{32}\right)=0\)
Vì \(\frac{1}{99}+\frac{1}{49}+\frac{1}{32}\ne0\)
=> x - 100 = 0
=> x = 100
Chúc bạn học tốt
Đúng 4
Bình luận (0)
có người khác trả lời trước rồi nên chị ko trả lời đâu nhé em trai
Đúng 2
Bình luận (0)
(2+4+6+...+100) - (1+3+5+...+99) = ?
1 x 2 + 2 x 3 + 3 x 4 + ... + 99 x 100 = ?
3 x 4 + 4 x 5 + 5 x 6 + ... + 149 x 150 = ?
1 + (1 + 2) + ( 1 + 2 + 3) + (1 + 2 + 3 + 4) + ....... + (1 + 2 + 3 + ... + 99)
----------------------------------------------------------------------------------------------------------- ( gạch ngang phân số )
1 x 99 + 2.98 + 3.97 + ...... + 99 x 1
Xem thêm câu trả lời
Tìm x:
a)39.(5-2x)=39
b)x+(x+1)+(x+3)+...+(x+99)=1240
c) (x+1)+(x+3)+...+(x+99)=7500
d)1+2+3+...+100=1/2.x(x+1). (x thuộc N)
39.(5 - 2\(x\)) = 39
5 - 2\(x\) = 39 : 39
5 - 2\(x\) = 1
2\(x\) = 5 - 1
2\(x\) = 4
\(x=4:2\)
\(x=2\)
Vậy \(x=2\)
Đúng 0
Bình luận (0)
x.1 +x.2+x.3+...+x.99=495 trả lời hộ mink nhé
\(x.1+x.2+x.3+....+x.99=495\)
<=> \(x.\left(1+2+3+...+99\right)=495\)
<=> \(x.\left\{\left(99+1\right).\left[\left(99-1\right):1+1\right]:2\right\}=495\)
<=> \(x.4950=495\)
<=> \(x=\frac{495}{4950}=\frac{1}{10}\)
Đúng 0
Bình luận (0)
x.1 +x.2+x.3+...+x.99=495
=>x.(1+2+3+...+99)=495
=>x.\(\frac{\left(1+99\right).99}{2}=495\)
=>x.4950=495
=>x=\(\frac{495}{4950}\)
=>x=1/10
Đúng 0
Bình luận (0)
Tìm x
1*2+2*3+3*4+......+99*101/x^2 +(x^2+1)+(x^2+2)+....+(x^2+99)=50 116/131
VN
20 tháng 8 2023 lúc 13:52
a) Thực hiện phép tính
( 1 - 1/2 ) x ( 1 - 1/3 ) x ( 1 - 1/4 ) x ( 1 - 1/5 ) x ... x ( 1 - 1/99 )
b) Tìm X biết
( X +1/2 ) + ( X +1/6 ) + ( X +1/12 ) + ( X +1/20 ) + ... + ( X +1/90 ) = 99/10
Tìm GTNN:
a) A= |x-1| + |x-2| + |x-3| + ... + |x-99|
b) B = |2x-3|+ |x-6| + |x+1|