\(\frac{9^4.27^5.3^6.3^4}{3^8.81^4.234.8^2}\)
Rút gọn phân số : a) M = 9^4.27^5.3^6.3^4/3^8.81^4.234.8^2
Lời giải:
\(M=\frac{9^4.27^5.3^6.3^4}{3^8.81^4.234.8^2}=\frac{(3^2)^4.(3^3)^5.3^6.3^4}{3^8.(3^4)^4.2.3^2.13.(2^3)^2}\)
\(=\frac{3^8.3^{15}.3^6.3^4}{3^8.3^{16}.2.3^2.13.2^6}=\frac{3^{33}}{3^{26}.2^7.13}=\frac{3^7}{2^7.13}\)
Rút gọn phân số: M=\(\frac{9^4.27^5.3^6.3^4}{3^8.81^4.234.8^2}\)
\(M=\frac{\left(3^2\right)^4.\left(3^3\right)^5.3^6.3^4}{3^8.\left(3^4\right)^4.3^5.\left(2^3\right)^2}=\frac{3^8.3^{15}.3^6.3^4}{3^8.3^{16}.3^5.2^6}=\frac{3^{29}.3^4}{3^{29}.2^6}=\frac{1.81}{1.64}=\frac{81}{64}\)
M = \(\frac{9^4.27^5.3^6.3^4}{3^8.81^4.234.8^2}\)
*Rút gọn nhé
\(M=\frac{9^4.27^5.3^6.3^4}{3^8.81^4.243.8^2}\)
\(M=\frac{\left(3^2\right)^4.\left(3^3\right)^5.3^6.3^4}{3^8.\left(3^4\right)^4.\left(3^5\right).\left(2^3\right)}\)
\(M=\frac{3^8.3^{15}.3^6.3^4}{3^8.3^{16}.3^5.8}\)
\(M=\frac{3^{33}}{3^{29}.8}\)
\(M=\frac{3^4}{1.8}\)
\(M=\frac{81}{8}\)
Chúc bạn học tốt !!!
Sửa hộ mk :
\(8^2=2^9\)
Kết quả : \(\frac{81}{512}\)
( tự suy nghĩ đề )
\(M=\frac{9^4.27^5.3^6.3^4}{3^8.81^4.234.8^2}\)
\(N=\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(M=\frac{9^4.27^5.3^6.3^4}{3^8.81^4.234.8^2}=\frac{\left(3^2\right)^4.\left(3^3\right)^5.3^6.3^4}{3^8.\left(3^4\right)^4.3^5.\left(2^3\right)^2}\)
\(M=\frac{3^8.3^{15}.3^6.3^4}{3^{18}.3^{16}.3^5.2^6}=\frac{81}{64}\)
\(N=\frac{4^6.9^5.6^9.120}{8^4.3^{12}-6^{11}}=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(N=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}=\frac{2.6}{3.5}\)
\(N=\frac{4}{5}\)
rút gọn phân số sau
M = \(\frac{9^4.27^5.3^6.3^4}{3^8.81^4.234.8^2}\)
N = \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
ai nhanh mik tick cho
11/4 giờ = bao nhiêu phút
lop6 đi mà học
\(M=\frac{9^4.27^5.3^6.3^4}{3^8.81^4.243.8^2}\)
Các bạn giả cụ thể chặt chẽ hộ mình nhé ai trả lời nhanh mình tick cho tks các bạn!!!
\(\dfrac{8^3.9^4-\left(-2\right)^8.81^2}{16^2.81^2+4^4.27^3}\)
giúp em với mng =(
\(=\dfrac{\left(2^3\right)^3.\left(3^2\right)^4-2^8.\left(3^4\right)^2}{\left(2^4\right)^2.\left(3^4\right)^2+\left(2^2\right)^4.\left(3^3\right)^3}=\dfrac{2^9.3^8-2^8.3^8}{2^8.3^8+2^8.3^9}=\)
\(=\dfrac{2^8.3^8.\left(2-1\right)}{2^8.3^8.\left(1+3\right)}=\dfrac{1}{4}\)
tính \(\frac{15.3^{11}+4.27^4}{9^7}\)
\(\frac{4^6.3^49^3}{6^{12}}\)
\(\frac{2^{11}-2^3}{2^9-2}\)
tính giúp mik nhé
\(A=\frac{9^{4^{ }}.27^5.3^6.3^4}{3^8.814.234.8^2}.\frac{ }{ }\)Gúp mình nhé
Tính theo phân tích các số ấy ra thừa số nguyên tố chứ ko giải phương trình nhé
\(A=\frac{9^4.27^5.3^6.3^4}{3^8.814.234.8^2}=\frac{\left(3^2\right)^4.\left(3^3\right)^5.3^{10}}{3^8.2.407.2.3^2.13.\left(2^3\right)^2}=\frac{3^8.3^{15}.3^{10}}{2^8.3^{10}.13.407}=\frac{3^{23}}{2^8.13.407}\)