GIÚP MIK Ạ

\(d)8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)

\(=\dfrac{8.7+2}{7}-\left(\dfrac{3.9+4}{9}+\dfrac{4.7+2}{7}\right)\)

\(=\dfrac{58}{7}-\left(\dfrac{31}{9}+\dfrac{30}{7}\right)\)

\(=\dfrac{58}{7}-\dfrac{31}{9}-\dfrac{30}{7}\)

\(=\left(\dfrac{58}{7}-\dfrac{30}{7}\right)-\dfrac{31}{9}\)

\(=\left(\dfrac{58-30}{7}\right)-\dfrac{31}{9}\)

\(=\dfrac{28}{7}-\dfrac{31}{9}\)

\(=\dfrac{28.9}{7.9}-\dfrac{31.7}{9.7}\)

\(=\dfrac{252}{63}-\dfrac{217}{63}\)

\(=\dfrac{252-217}{63}\)

\(=\dfrac{35}{63}\)

\(=\dfrac{5}{9}\)

=\(\dfrac{58}{7}\)-\((\dfrac{31}{9}\)+\(\dfrac{30}{7})\)

=\(\dfrac{58}{7}\)-\(\dfrac{31}{9}\)-\(\dfrac{30}{7}\)

=(\(\dfrac{58}{7}\)-\(\dfrac{30}{7}\))-\(\dfrac{31}{9}\)

=4-\(\dfrac{31}{9}\)

=\(\dfrac{5}{9}\)

`1+1/3=4/3`

`=>1/(1+1/3)=1:4/3=3/4`

`=>B=(1-1/3+3/4)/(1-1/3-3/4)`

`=(2/3+3/4)/(2/3-3/4)`

`=17/12:(-1/12)`

`=-17`

\(10^3+\left[120:\left(2^2.3.5-3^2.5\right)\right]\)

\(=1000+\left[120:\left(4.3.5-9.5\right)\right]\)

\(=1000+120:\left(60-45\right)\)

\(=1000+\left[120:15\right]=1000+8=1008\)

\(c,=\left(2\sqrt{3}-6\sqrt{2}+5\sqrt{3}\right)\sqrt{3}+5\sqrt{6}\\ =\left(7\sqrt{3}-6\sqrt{2}\right)\sqrt{3}+5\sqrt{6}\\ =21-6\sqrt{6}+5\sqrt{6}=21-\sqrt{6}\\ f,=\sqrt{\dfrac{\left(\sqrt{3}-3\right)^2}{3-\sqrt{3}}}=\sqrt{\dfrac{\left(3-\sqrt{3}\right)^2}{3-\sqrt{3}}}=\sqrt{3-\sqrt{3}}\\ i,=\dfrac{7-4\sqrt{3}+7+4\sqrt{3}}{7^2-\left(4\sqrt{3}\right)^2}=\dfrac{14}{49-48}=\dfrac{14}{1}=14\)

\(e,=2\sqrt{3\cdot2}-2\sqrt{3}\cdot3+2^2-2\cdot2\cdot\sqrt{3}+\left(\sqrt{3}\right)^2+6\sqrt{3}\\ =2\sqrt{6}-6\sqrt{3}+4-4\sqrt{3}+3+6\sqrt{3}\\ =2\sqrt{6}-4\sqrt{3}+7\)

e,=2√3⋅2−2√3⋅3+22−2⋅2⋅√3+(√3)2+6√3=2√6−6√3+4−4√3+3+6√3=2√6−4√3+7

\(=2\sqrt{3.2}-3.2\sqrt{3}+2^2-2.2.\sqrt{3}+\left(\sqrt{3}\right)^2+6\sqrt{3}\)

\(=2\sqrt{6}-6\sqrt{3}+4-4\sqrt{3}+3+6\sqrt{3}\)

\(=2\sqrt{6}-4\sqrt{3}+7\)

\(a,\dfrac{-13}{5}-\dfrac{-7}{15}.\dfrac{120}{63}+\dfrac{4}{5}\\ =\dfrac{-13}{5}+\dfrac{8}{9}+\dfrac{4}{5}\\ =\dfrac{-77}{45}+\dfrac{4}{5}\\ =\dfrac{-41}{45}\\ b.\left(7\dfrac{5}{9}+2\dfrac{2}{3}\right)-5\dfrac{2}{9}\\ =\left(\dfrac{68}{9}+\dfrac{8}{3}\right)-\dfrac{47}{9}\\ =\dfrac{92}{9}-\dfrac{47}{9}\\ =5\)

2)\(-\dfrac{13}{5}--\dfrac{7}{15}.\dfrac{120}{63}+\dfrac{4}{5}\)
\(=-\dfrac{13}{5}+\dfrac{7.15.8}{15.9.7}+\dfrac{4}{5}\)
\(=-\dfrac{13}{5}+\dfrac{8}{9}+\dfrac{4}{5}\)
\(=\left(-\dfrac{13}{5}+\dfrac{4}{5}\right)+\dfrac{8}{9}\)
\(=-\dfrac{9}{5}+\dfrac{8}{9}\)
\(=\dfrac{-81+40}{45}=-\dfrac{41}{45}\)
3)\(\left(7\dfrac{5}{9}+2\dfrac{2}{3}\right)-5\dfrac{2}{9}\)
\(=\left(7\dfrac{5}{9}-5\dfrac{2}{9}\right)+2\dfrac{2}{3}\)
\(=2\dfrac{1}{3}+2\dfrac{2}{3}\)
\(=5\)

a,−135−−715.12063+45=−135+89+45=−7745+45=−4145b.(759+223)−529=(689+83)−479=929−479=5a,−135−−715.12063+45=−135+89+45=−7745+45=−4145b.(759+223)−529=(689+83)−479=929−479=5