a-b=5

<=>(a-b)²=a²-2ab+b² =25

<=>a²+b²-2ab =33

<=>a²+b² = 33 (vì 2ab=8)

Ta có:

a³-b³= (a-b)(a²+ab+b²)

=5.(33+4) =185

Ta có: \(a+b=8\)

\(\Rightarrow\left(a+b\right)^2=8^2\)

\(\Rightarrow a^2+2ab+b^2=64\)

\(\Rightarrow a^2+2.10+b^2=64\)

\(\Rightarrow a^2+20+b^2=64\)

\(\Rightarrow a^2+b^2=44\)

\(\left(a-b\right)^2=a^2-2ab+b^2\)

\(=\left(a^2+b^2\right)-2.10\)

\(=44-20\)

\(=24\)

Vậy \(\left(a-b\right)^2=24\)

(a-b)² = a²-2ab+b²

= a²+2ab+b² -4ab

⁼(a+b)²- 4ab

=8² - 4.10

=64-40

=24

thanks

Evaluate the expression at

x³ + 12x + 48x + 64

= (x + 4)²

= (- 4 + 4)²

= 0²

= 0

Fill in the blank: ............

x³ - a = (x - 2)(x² + 2x + 4)

x³ - a = x³ - 8

a = 8

Fill in the blank: (x - 1)³ = x³ - 3x² + 3x - 1 Fill in the blank: (x + 1)³ = x³ + 3x² + 3x + 1
Evaluate , given and .
Answer:

a + b = 8

(a + b)² = 8²

a² + b² + 2ab = 64

a² + b² + 2 . 10 = 64

a² + b² + 20 = 64

a² + b² = 64 - 20

a² + b² = 44

(a - b)²

= a² - 2ab + b²

= 44 - 2 . 10

= 44 - 20

= 24
Given .
Evaluate A at .
Answer: A

A = (x - 5)(x² + 5x + 25) - x²(x + 3) + 3x²

= x³ - 125 - x³ - 3x² + 3x²

= - 125

Given .
Evaluate A at .
Answer: A

A = (x - 5)(2x + 1) - 2x(x - 3) + 3x= 2x² + x - 10x - 5 - 2x² + 6x + 3x= - 5Given a rectangle with dimension by . Find the area of the rectangle when and .
Answer: . Given and . Evaluate .Answer: a - b = 5(a - b)² = 5²a² - 2ab + b² = 25a² + b² - 2 . 4 = 25a² + b² - 8 = 25a² + b² = 25 + 8a² + b² = 33a³ - b³ = (a - b)(a² + ab + b²) = 5 . (33 + 4)= 5 . 37= 185
Given and . Evaluate .
Answer: a + b = 5(a + b)² = 5²a² + 2ab + b² = 25a² + b² + 2 . 4 = 25a² + b² + 8 = 25a² + b² = 25 - 8a² + b² = 17a³ + b³= (a + b)(a² - ab + b²)= 5 . (17 - 4)= 5 . 13= 65

5

minh cung chiu

chỗ tiếng việt chỗ tiếng anh là sao

cho dễ hỉu ý hjhj

mk nghĩ là -1

\(\frac{x^3+x^2-4x-4}{x^3+8x^2+17x+10}=\frac{x^2\left(x+1\right)-4\left(x+1\right)}{x^2\left(x+1\right)+7x\left(x+1\right)+10\left(x+1\right)}\)

\(=\frac{\left(x+1\right)\left(x^2-4\right)}{\left(x+1\right)\left(x^2+7x+10\right)}=\frac{\left(x+2\right)\left(x-2\right)}{x\left(x+2\right)+5\left(x+2\right)}\)

\(=\frac{\left(x+2\right)\left(x-2\right)}{\left(x+2\right)\left(x+5\right)}=\frac{x-2}{x+5}\Rightarrow a=-2;b=5\)

\(\Rightarrow\)\(a+b=-2+5=3\)