1/1x2 + 1/2x3 + 1/3x4 + ............. + 1/2009x2010
tinh M=1x2+2x3+3x4+...+2009x2010
Tính: B= 1x2+2x3+3x4+...+2009x2010
B= 1.2+2.3+3.4+...+2009.2010
=>3B=1.2.3+2.3.3+3.4.3+...+2009.2010.3
=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+2009.2010.(2011-2008)
=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+....+2009.2010.2011-2008.2009.2010
=2009.2010.2011
=>B=\(\frac{2009.2010.2011}{3}=2706866330\)
ta có: 1x2+2x3+3x4+....+n(n+1)
=1x(1+1)+2x(2+1)+3x(3+1)+....n(n+1)
=(1^2+2^2+3^2+¡+n^2)+(1+2+3+....+n)
=n(n+1)(2n+1)/6+n(n+1)/2
=[n(n+1)[(2n+1)+3]/6
thay n=2009=> B=\(\frac{2009.\left(2009+1\right).\left(2009.2+1\right)+3}{6}\)=2704847286
1/1x2+1/2x3+1/3x4+1/24x25
1/1x2+ 1/2x3+1/3x4+1/24x25
\(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+....+\dfrac{1}{24\times25}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{24}-\dfrac{1}{25}\)
\(=1-\dfrac{1}{25}\)
\(=\dfrac{24}{25}\)
\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+.....+\frac{1}{2009x2010}+\frac{1}{2010x2011}\)
Mấy bạn giúp mình nhé , mình đang gấp , 9h mình cần rồi , nhớ giải chi tiết nhé , thanks nhiều ( sẽ hậu tạ )
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2010}-\frac{1}{2011}\)
\(=1-\frac{1}{2011}\)
\(=\frac{2010}{2011}\)
=1/1-1/2+1/2-1/3+1/3-1/4+...+1/2010-1/2011
= 1 - 1/2011
= 2010/ 2011
Đáp số: 2010/2011
Chúy ý công thức: \(\frac{1}{n\left(n+1\right)}=\frac{1}{n}-\frac{1}{n+1}\)
= 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/2010 - 1/2011
= 1 - 1/2011
= 2010/2011
Đáp sô: 2010/2011
Chú ý công thưc: \(\frac{1}{n\left(n+1\right)}=\frac{1}{n}-\frac{1}{n+1}\)
Tính tổng S biết:
S = \(\frac{1}{1x2}\)+ \(\frac{1}{2x3}\)+ \(\frac{1}{3x4}\)+ ... + \(\frac{1}{2008x2009}\)+ \(\frac{1}{2009x2010}\)
S=1-\(\frac{1}{2}\)+\(\frac{1}{2}\)-\(\frac{1}{3}\)+...+\(\frac{1}{2009}\)-\(\frac{1}{2010}\)
S=1-\(\frac{1}{2010}\)
S=\(\frac{2009}{2010}\)
k nha bn
\(S=\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{2008\times2009}+\frac{1}{2009\times2010}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2008}-\frac{1}{2009}+\frac{1}{2009}-\frac{1}{2010}\)
\(=1-\frac{1}{2010}\)
\(=\frac{2009}{2010}\)
Vậy \(S=\frac{2009}{2010}\)
Học tốt #
s = 1- 1/2+ 1/2- 1/3+ 1/3- 1/4 ......-1/2008- 1/2009+ 1/2009- 1/2010
s =1- 1/2010
s = 2009/2010
(1/(1x2)/(2x3)/(3x4)):(1/(2x3)/(3x4)/(4x5)):...(1/(97*98)/(98*99)/(99*100))
(1/(1x2)/(2x3)/(3x4)):(1/(2x3)/(3x4)/(4x5)):...(1/(97*98)/(98*99)/(99*100
haizzz đáng tiếc tôi muốn ns là: ko bao f và đừng mong chờ OK
1/(1x2)/(2x3)/(3x4)):(1/(2x3)/(3x4)/(4x5)):...(1/(97*98)/(98*99)/(99*100
(1/(1x2)/(2x3)/(3x4)):(1/(2x3)/(3x4)/(4x5)):...(1/(97*98)/(98*99)/(99*100
Lên Qanda mà hỏi