\(A=\)\(\frac{6}{7}+\frac{1}{7}\times\frac{2}{7}+\frac{1}{7}\times\frac{5}{7}=\frac{6}{7}+\frac{1}{7}\left(\frac{2}{7}+\frac{5}{7}\right)\)

                                                                                                            \(=\frac{6}{7}+\frac{1}{7}\times1\)

                                                                                                            \(=\frac{6}{7}+\frac{1}{7}\)

                                                                                                             \(=1\)

 Cách 1:                                                      \(B=\frac{4}{9}\times\frac{13}{3}-\frac{4}{3}\times\frac{40}{9}\)

                                                                      \(=\frac{52}{27}-\frac{160}{27}\)

                                                                      \(=-4\)

K cho mk nhé thks bn nhiều

~CHÚC BẠN HỌC TỐT~

A=6/7+1/7(2/7+5/7)

 =6/7+1/7.1

 =6/7+1/7

 =1

A=6/7+1/7.2/7+1/7.5/7

A=6/7+1/7.(2/7+5/7)

A=6/7+1/7.7/7

A=6/7+1/7.1

A=7/7=1

B=4/9.13/3-4/3.4/9

B=4/9.(13/3-4/3)

B=4/9.9/3

B=4/9.3

B=12/9

\(A=\dfrac{6}{7}+\dfrac{1}{7}\cdot\dfrac{2}{7}+\dfrac{1}{7}\cdot\dfrac{5}{7}\\ =\dfrac{6}{7}+\dfrac{1}{7}\cdot\left(\dfrac{2}{7}+\dfrac{5}{7}\right)\\ =\dfrac{6}{7}+\dfrac{1}{7}\cdot1\\ =\dfrac{6}{7}+\dfrac{1}{7}\\ =1\\\)

4⁵ x 9⁴ - 2 x 6⁹=6718464 - 20155392 = -13436928

2¹⁰ x 3⁸ + 6⁸ x 20=6718464+33592320=40310784

 15,46 + 20,09 + 11,3+ 4,18

=35,55+11,3+4,18

=46,85+4,18

=51,03

 = 51,03

k mk nha

CẢM ƠN BẠN NHIỀU

B1

Số nhóm biểu thức nhò là

(2001+3)/2+1=1003(số)
mà giá trị mỗi biểu thức là 1

=> 1+1*1003=1004

\(A=8\frac{4}{17}-\left(2\frac{5}{9}+3\frac{4}{17}\right)\)

\(A=8\frac{4}{17}-2\frac{5}{9}-3\frac{4}{17}\)

\(A=\left(8\frac{4}{17}-3\frac{4}{17}\right)-\frac{23}{9}\)

\(A=5-\frac{23}{9}\)

\(A=\frac{45}{9}-\frac{23}{9}\)

\(A=\frac{22}{9}\)

\(A=8\frac{4}{7}-2\frac{5}{9}-3\frac{4}{7}\)

\(A=\left(8\frac{4}{7}-3\frac{4}{7}\right)-2\frac{5}{9}\)

\(A=5-2\frac{5}{9}\)

\(A=4+1-2\frac{5}{9}\)

\(A=4+1-\frac{23}{9}\)

\(A=4+\frac{-14}{9}\)

\(A=1\frac{5}{9}\)

a, Ta có: \(A=\left|x+2\right|+\left|9-x\right|\ge\left|X+2+9-x\right|=11\)

Dấu "=' xảy ra khi \(\left(x+2\right)\left(9-x\right)\ge0\Leftrightarrow-2\le x\le9\)

Vậy Min_A = 11 khi -2 =< x =< 9

b, Vì \(\left(x-1\right)^2\ge0\Rightarrow-\left(x-1\right)^2\le0\Rightarrow B=\frac{3}{4}-\left(x-1\right)^2\le\frac{3}{4}\)

Dấu "=" xảy ra khi x = 1

Vậy Max_B = 3/4 khi x=1

Ta có :\(A=\left|x+2\right|+\left|9-x\right|\ge\left|x+2+9-x\right|=11\)

Vậy \(A_{min}=11\) khi \(2\le x\le9\)

\(\frac{4}{9}.\frac{13}{3}-\frac{4}{3}.\frac{40}{9}=\frac{4}{9}.\frac{13}{3}-\frac{4}{9}.\frac{40}{3}=\frac{4}{9}\left(\frac{13}{3}-\frac{40}{3}\right)=\frac{4}{9}. \left(-9\right)=-4\)

Ủng hộ mk nha

b có thể tính nhanh đc ko