a.5/7+x/35=4/5
A X + 4/5= 45/5 -( 3/7 + 3/5)
B. 5/7 + X/35 = 4/5
`x + 4/5= 45/5 -( 3/7 + 3/5)`
`=> x+ 4/5=9 - 36/35`
`=> x+ 4/5=279/35`
`=> x= 279/35 -4/5`
`=>x= 251/35`
__
`5/7 + x/35 = 4/5`
`=> x/35 = 4/5-5/7`
`=> x/35 =28/35 - 25/35`
`=> x/35= 3/35`
`=>x=3`
`@ `\(MinYewCou\)
A X + 4/5= 45/5 -( 3/7 + 3/5)
B. 5/7 + X/35 = 4/5
\(a,x+\dfrac{4}{5}=\dfrac{45}{5}-\left(\dfrac{3}{7}+\dfrac{3}{5}\right)\)
\(x+\dfrac{4}{5}=9-\dfrac{3}{7}-\dfrac{3}{5}\)
\(x+\dfrac{4}{9}=\dfrac{279}{35}\)
\(x=\dfrac{279}{35}-\dfrac{4}{9}\)
\(x=\dfrac{251}{35}\)
\(b,\dfrac{5}{7}+\dfrac{x}{35}=\dfrac{4}{5}\)
\(\dfrac{5}{7}+\dfrac{x}{35}-\dfrac{4}{5}=0\)
\(\dfrac{25}{35}+\dfrac{x}{35}-\dfrac{28}{35}=0\)
\(25+x-28=0\)
\(x=3\)
a,\(x\)\(+\)\(\dfrac{4}{5}\)=\(\dfrac{45}{4}\)\(-\)\((\)\(\dfrac{7}{5}\)+\(\dfrac{3}{5}\)\()\)
b,\(\dfrac{5}{7}\)+\(\dfrac{x}{35}\)=\(\dfrac{4}{5}\)
12:05
A)28 - x / 35 = 5/7
B)x + 11/ 35 = 4/5
a/ \(\frac{28-x}{35}=\frac{5}{7}\Rightarrow7\left(28-x\right)=35.5\Rightarrow196-7x=175\Rightarrow7x=21\Rightarrow x=3\)
b/ \(\frac{x+11}{35}=\frac{4}{5}\Rightarrow5\left(x+11\right)=35.4\Rightarrow5x+55=140\Rightarrow5x=85\Rightarrow x=17\)
Tính x biết
A X + 4/5= 45/5 -( 3/7 + 3/5)
B. 5/7 + X/35 = 4/5
\(x+\frac{4}{5}=\frac{45}{5}-\left(\frac{3}{7}+\frac{3}{5}\right)\)
\(x+\frac{4}{5}=9-\frac{36}{35}\)
\(x+\frac{4}{5}=\frac{279}{35}\)
\(\Rightarrow x=\frac{251}{35}\)
\(x+\frac{4}{5}=\frac{45}{5}-\left(\frac{3}{7}+\frac{3}{5}\right)\)
\(\Leftrightarrow x+\frac{4}{5}=9-\left(\frac{3}{7}+\frac{3}{5}\right)\)
\(\Leftrightarrow x+\frac{4}{5}=9-\frac{3}{7}-\frac{3}{5}\)
\(\Leftrightarrow x+\frac{4}{5}=\frac{315}{35}-\frac{15}{35}-\frac{21}{35}\)
\(\Leftrightarrow x+\frac{4}{5}=\frac{279}{35}\)
\(\Leftrightarrow x=\frac{279}{35}-\frac{4}{5}\)
\(\Leftrightarrow x=\frac{251}{35}\)
\(\frac{5}{7}+\frac{x}{35}=\frac{4}{5}\)
\(\Leftrightarrow\frac{25}{35}+\frac{x}{35}=\frac{28}{35}\)
\(\Leftrightarrow25+x=28\)
\(\Leftrightarrow x=28-25\)
\(\Leftrightarrow x=3\)
tìm x
a)x+ 4/5=4/5+ (3/7+3/5) b) 5/7+ x/35=4/5
a, ta thấy cả hai vế đều có 4/5 mà lại bằng nhau nên x bằng số hạng còn lại ở vế phải
x=3/7+3/5
x=36/35
b,x là số hạng chưa biết nên
x=4/5-5/7
x=3/35
cảm ơn Kiều Ngọc Lan tớ đứng đầu olm lớp 4 đấy
a) x - = b) . c)
) : e) f) .
x
x
d x x x x x
3 13 2 4 3 7 2
1 3
5 25 3 5 10 15 3
4 5 1 7 2 11 1 1
3 15 1 3
5 7 6 5 5 2 3 2
tìm x
x+4/5=4/5+(3/7+3/5
5/7+x/35=4/5
`x+4/5=4/5+(3/7+3/5)`
`=> x+4/5=4/5+36/35`
`=> x+4/5= 64/35`
`=>x= 64/35 -4/5`
`=>x= 64/35 - 28/35`
`=>x= 36/35`
`----`
`5/7 + x/35 =4/5`
`=>x/35 =4/5-5/7`
`=>x/35 =28/35 - 25/35`
`=> x/35= 3/35`
`=>x=3`
Tính nhẩm:
7 x 5 =
7 x 6 =
7 x 2 =
7 x 4 =
35 : 7 =
42 : 7 =
14 : 7 =
28: 7 =
35 : 5 =
42 : 6 =
14 : 2 =
28 : 4 =
Học sinh nhẩm và ghi kết quả như sau:
7 x 5 = 35
7 x 6 = 42
7 x 2 = 14
7 x 4 = 28
35 : 7 =5
42 : 7 = 6
14 : 7 = 2
28: 7 =4
35 : 5 = 7
42 : 6 = 7
14 : 2 = 7
28 : 4 = 7