4.Tính:
E = 9/2 + 9/6 + 9/12 + 9/16 + ... + 9/2016 x 2015
ND
Những câu hỏi liên quan
So sánh các biểu thức
a) A= 2015 x 2017 + 2016 x 2018 và B=2016^2+2017^2 -2
b) M=(9+1).(9^2+1).(9^4+1).(9^8+1).(9^16+1).(9^32+1) và N=9^64-1
4/3x (16/9)2015x (9/16)2016
So sánh:
a) A=9^10 và B= ( 8^9+7^9+6^9+...+2^9+1^9)
b) P= 2013/2014 + 2014/2015 + 2015/2016 với Q= 2013+2014+2015 / 2014+2015+2016
A=1-2+3+4-5-6+7+8-9-...+2007+2008-2009-2010
B=-1-2+3+4-5-6+7+8-9-10+11+12-...-2013-2014+2015+2016
C=(2+4+6+8+...+2014)-(3+5+7+9...+2011)
A = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + ... + 2005 + 2006 - 2007 - 2008 + 2009 + 2010 ( có 2010 số )
A = ( 1 + 2 - 3 - 4 ) + ( 5 + 6 - 7 - 8 ) + .... + ( 2005 + 2006 - 2007 - 2008 ) + ( 2009 + 2010 )
A = ( - 4 ) + ( - 4 ) + ... + ( - 4 ) + 4019 ( có 503 số )
A = ( - 4 ) . 502 + 4019
A = - 2008 + 4019
A = 2011.
CHÚC LÀM BÀI VUI VẺ
a,
x-2/3-2/15-2/35-2/63=1/9
b
(x+1
3)+(x+1/9)+(x+1/27)+(x+1/81)=56/81
c,
(1/3*5+1/5*7+1/7*9+.....+1/19*21)*x=9/7
d,3+5+7+...+2015/2+4+6+...+2016+x=1
e,2/6+2/12+2/20+...+2/x*(x+1)=2013/2015
(9/16)\(^{2016}\).(16/9)\(^{2015}\).4/3
\(\left(\dfrac{9}{16}\right)^{2016}.\left(\dfrac{16}{9}\right)^{2015}.\dfrac{4}{3}\)
\(=\left[\left(\dfrac{3}{4}\right)^2\right]^{2016}.\left[\left(\dfrac{4}{3}\right)^2\right]^{2015}.\dfrac{4}{3}\)
\(=\left(\dfrac{3}{4}\right)^{2018}.\left(\dfrac{4}{3}\right)^{2017}.\dfrac{4}{3}\)
\(=\left(\dfrac{3}{4}\right)^{2018}.\left(\dfrac{4}{3}\right)^{2018}\)
\(=\left(\dfrac{3}{4}.\dfrac{4}{3}\right)^{2018}\)
\(=\left(\dfrac{1}{1}.\dfrac{1}{1}\right)^{2018}\)
\(=1^{2018}\)
\(=1\)
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A=-1-2+3+4-5-6+7+8-9-10+11+12-.. ..-3013-2014+2015+2016
A=(0-1-2+3)+(4-5-6+7)+...+((2012-2013-2014+2015)+2016
A=0+0+...+0
A=2016
Vậy A=2016
nhé Bạn
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A=1-2+3+4-5-6+7+8-9-10+11+12-...-2014+2015+2016
A=(0-1-2+3)+(4-5-6+7)+...+(2012-2013-2014+2015)+2016
A=0+0+...+2016
A=2016
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A= -1-2+3+4-5-6+7+8-9-10+11+12-...-2013-2014+2015+2016
A=(0-1-2+3)+(4-5-6+7)+...+((2012-2013-2014+2015)+2016
A=0+0+...+0
A=2016
Vậy A=2016
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Ta có:
A = -1 – 2 + 3 + 4 – 5 – 6 + 7 + 8 – 9 – 10 + 11 + 12 - ... – 2013 – 2014 + 2015 + 2016
A = (0 – 1 – 2 + 3) + (4 – 5 – 6 + 7) + ... + (2012- 2013 – 2014 + 2015) + 2016
A = 0 + 0 + ... + 0
A = 2016
Vậy A = 2016
#Mạt Mạt#